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2 years ago

A substance with a mass of 50.0 g has a temperature change of 40.0

Chemistry

2 answers:

grigory [225]2 years ago

7 0

Answer:

Mass=50.0g

H=670J

change in temperature=40

using. c=h÷m×change in temperature

c=670÷50×40

C=670÷2000

C=0.335jkg-1k-1

Alex2 years ago

6 0

Answer: The specific heat of a substance with a mass of 50. 0g and a temperature change of 40. 0 degrees whne it absorbs 670 J of heat is 337 J/kg. K

Explanation:

Specific heat of a substance is said to be the energy required for an increase in temperature by 1°C in the unit of J/Kg. K

Formula of Specific heat:

Q = mcΔθ

Q represents the quantity of heat

m represents the mass of the substance in Kilograms = 50. 0g÷ 1000 = 0.05kg

c represents the specific heat capacity of the substance = ?

θ represents the temperature change = 40° C

Specific heat, c = Q ÷ mΔθ

= 670 ÷ 0.05 × 40

= 670 ÷ 2

= 335 J/ Kg. K

Therefore, the specific heat of the substance is 335 J/kg. K

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Ascorbic acid (H2C6H6O6; H2Asc for this problem), known as vitamin C, is a diprotic acid (Ka1= 1.0x10–5 and Ka2= 5x10–12) found

Igoryamba

Answer:

The concentrations are :

$[HAsc^-]=0.000702 M$

$[Asc^{2-}]=5.92\times 10^{-8} M$

The pH of the solution is 3.15.

Explanation:

$H_2Asc\rightleftharpoons HAs^-+H^+$ $K_{a1}=1.0\times 10^{-5}$

Initial

c 0 0

Equilibrium

c-x x x

$K_{a1}=\frac{[HAs^-][H^+]}{[H_2Asc]}$

$1.0\times 10^{-5}=\frac{x\times x}{(c-x)}$

$1.0\times 10^{-5}=\frac{x^2}{(0.050-x)}$

Solving for x:

x = 0.000702 M

$[HAsc^-]=0.000702 M$

$HAsc^-\rightleftharpoons As^{2-}+H^+$ $K_{a2}=5\times 10^{-12}$

Initially

x 0 0

At equilibrium ;

(x - y) y y

$K_{a2}=\frac{[As^{2-}][H^+]}{[HAsc^-]}$

$5\times 10^{-12}=\frac{y\times y}{(x-y)}$

$5\times 10^{-12}=\frac{y^2}{(x-y)}$

Putting value of x = 0.000702 M

$5\times 10^{-12}=\frac{y^2}{(0.000702 -y)}$

$y=5.92\times 10^{-8} M$

$[Asc^{2-}]=5.92\times 10^{-8} M$

Total concentration of $[H^+]=x+y=0.000702 M+5.92\times 10^{-8} M=7.0206\times 10^{-4} M$

The pH of the solution :

$pH=-\log[H^+]$

$pH=-\log[7.0206\times 10^{-4} M}=3.15$

7 0

3 years ago

Equation for the reaction btn nitric acid and metal X whose valence is 3

viva [34]

(a) Reaction of nitric acid with non-metal:
C+4HNO
3

⟶CO
2

+2H
2

O+4NO
2

S+6HNO
3

⟶H
2

SO
4

+2H
2

O+6NO
2

(b) Nitric acid showing acidic character:
K
2

O+2HNO
3

⟶2KNO
3

+H
2

O
ZnO+2HNO
3

⟶Zn(NO
3

)
2

+H
2

O
(c) Nitric acid acting as oxidizing agent
P
4

+20HNO
3

⟶4H
3

PO
4

+4H
2

O+20NO
2

3Zn+8HNO
3

⟶3Zn(NO
3

)
2

+4H
2

O+2NO

hope that helps you please mark brainliest

3 0

2 years ago

To make a Br2 bond, how many total valence electrons are required?

lapo4ka [179]

Answer:

2. 14

Explanation:

To form Br₂ bond, a total of 14 electrons are needed.

Bromine is an element in the 7th group on the periodic table. It has 7 valence electrons.

In forming the bromine gas, the two atoms of bromine shares 7 electrons each.
These electrons are from their outermost shell.
The outermost shell is the valence shell.
So, two atoms donating 7 electrons gives 14 electrons.

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svetoff [14.1K]

Answer:

Explanation:

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