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3 years ago

7

I need help on #2 a and b. please explain steps and answer

1 answer:

choli [55]3 years ago

3 0

It's been awhile since i've balanced equations :O

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Help anyone can help me do this question,I will mark brainlest.

Anettt [7]

Answer:

12 grams

Explanation:

if you used the transformation equation you would end up with 12 grams

4 0

3 years ago

a 20ml sample of hcl was titrated with the 0.0220 M Naoh. to reach the endpoint required 23.72 mL of the NaOh. Calculate the mol

Y_Kistochka [10]

Answer:

Molarity of HCl=0.026092M

Explanation:

The equation for the reaction is;

HCl + NaOH ⇒ NaCl + H2O

Using the formular, $\frac{C_{A}V_{A}}{C_{B}V_{B} }=\frac{nA}{nB}$ ..........equ1

where $C_{A}$ is the concentration of Acid,

$V_{A}$ is volume of acid

$C_{B}$ is concentration of the base

$V_{B}$ is volume of the base

nA is the number of moles of Acid

nB is number of moles of base

nA = 1, nB=1 , $V_{A}=20ml$ , $C_{B}=0.022M$ , $V_{B}=23.72mL$

we will input these values into equation1 to solve for $C_{A}$

$\frac{C_{A}*20}{0.022*23.72}=\frac{1}{1}$

$C_{A}*20=0.022*23.72$

$C_{A}=0.026092M$

7 0

3 years ago

An electrode has a potential of 1.201 V with respect to a saturated silver-silver chloride electrode. What would the electrodes

fredd [130]

Answer:

The potential wrt. calomel is 1.254 V

Explanation:

Given:

Potential wrt. silver chloride $E_{Ag} = 1.201$ V

Potential wrt. saturated silver chloride $E = 0.197$ V

Potential wrt. SCE $E_{Hg} = 0.241$ V

Now potential wrt. hydrogen is given by,

$= 1.201- 0.197$

$= 1.004$ V

And we find for potential wrt. calomel,

$=$ potential wrt. hydrogen + potential wrt. SEC

$= 1.004 +0.241$

$= 1.254$ V

Therefore, the potential wrt. calomel is 1.254 V

7 0

3 years ago

Convert 4.500000000 to scientific notation

aniked [119]

I think it’s 4.5 x 10^9

7 0

3 years ago

What protects living things from too much ultraviolets radiation?

mixas84 [53]

The ozone layer of the Earth's atmosphere is what protects living things from too much ultraviolet radiation, if that's what you're asking about.

8 0

3 years ago