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Nostrana [21]
2 years ago
10

11. How many molecules of oxygen will be consumed when 33.6 liters of water is produced?

Chemistry
1 answer:
Andre45 [30]2 years ago
3 0

Answer:

67.2 litres of oxygen will be consumed

Explanation:

<u><em>Step 1 : Write the balanced chemical equation:</em></u>

2H₂ + O₂ → 2H₂O

<u><em>Step 2: find the ratio of O₂ : H₂O</em></u>

O₂ : H₂O

1 : 2

67.2 : 33.6

Thus, 67.2 litres of oxygen will be consumed

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Calculate the value of the equilibrium constant, Kc, for the reaction below, if 0.208 moles of sulfur dioxide gas, 0.208 moles o
Harman [31]
First, we convert the moles of each substance into the concentration using the volume of the reactor.
[SO₃] = 0.425/1.5 = 0.283 M
[SO₂] = 0.208 / 1.5 = 0.139 M
[O₂] = 0.208/1.5 = 0.139 M
The equilibrium constant is calculated by:
Kc = [SO₃]² / [O₂][SO₂]²
Kc = (0.283)²/(0.139)(0.139)²
Kc = 29.8 = 2.98 x 10¹

The answer is C
8 0
3 years ago
If a young girl learned that it would be 0° C, or 32° F, the next
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Answer:

Cold

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Because 0°C And below or 32°F Refers To Cold Weather

7 0
2 years ago
2. This graph shows the energy involved in a reaction involving two molecules. Describe what is happening or what the state of t
blagie [28]
If you think of it endothermic is when there is energy needed for the reaction to occur and exothermic is when the reaction releases energy
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3 years ago
g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertaint
diamong [38]

Answer:

The value  is   L  =  0.985 \pm 0.00801 \  g

Explanation:

From the question we are told that

  The  molar mass of CaCO_3 is  MW  =  100.085 \  g/mol

   The  total mass is  m_g  = 12.3 \ g

   The uncertainty of the total mass is \Delta g  = 0.1

Generally the molar weight of calcium is M_c  =  40 g/mol

 The percentage of calcium in calcite is mathematically represented as

          C =  \frac{40.07}{100.085} * 100

          C =  40.03 \%

Generally the mass of each sample is mathematically represented as

     m=  \frac{m_g}{5}

     m=  \frac{12.3}{5}

     m= 2.46 \  g

Generally mass of calcium present in a single sample is mathematically represented as

        m_c = 2.46 *  \frac{40.04}{100}

       m_c = 0.985 \  g

The  uncertainty of  mass of a single sample is mathematically represented as

      k  =  \frac{\Delta g }{5}

        k  =  \frac{0.1 }{5}

       k  =  0.02\  g

The  uncertainty of  mass of calcium in a single sample is mathematically represent

         G  =  \frac{0.02 *  40.04}{ 100}

          G  =  0.00801 \  g

Generally the average mass of calcium in each sample is  

          L  =  0.985 \pm 0.00801

6 0
3 years ago
Convert 1.60 x 107 cm to mm in scientific notation <br><br>please help
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Answer:

4.8x10^9

Explanation:

7 0
3 years ago
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