All categories

2 years ago

Test anxiety symptoms can include

Chemistry

2 answers:

Ber [7]2 years ago

5 0

D.) all of the above

AfilCa [17]2 years ago

4 0

Answer:

D.) All of the above

Explanation:

Anxiety can cause sweating, chaky hands, headaches etc

You might be interested in

Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi

uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is $2.9^0C$

Explanation:

Elevation in boiling point:

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of pure carbon disulfide= $46.2^oC$

$k_b$ = boiling point constant = $2.34^0Ckg/mol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute = 35.0 g

$w_1$ = mass of solvent (carbon disulphide) = 397.7 g

$M_2$ = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

$(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}$

$T_b=49.1^0C$

Therefore, the change in boiling point is $(49.1-46.2)^oC=2.9^0C$

5 0

3 years ago

Why do lungfish walk on land?

nordsb [41]

Answer:

The new findings support the theory that walking first arose underwater, preceding the move onto land and the development of toes and limbs adapted to land perambulation.

6 0

2 years ago

What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi

insens350 [35]

Explanation:

Formula to calculate standard electrode potential is as follows.

$E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}$

= 0.535 - 1.065

= - 0.53 V

Also, it is known that relation between $E^{o}_{cell}$ and K is as follows.

$E^{o}_{cell} = \frac{RT}{nF} \times ln K$

ln K = $\frac{nFE^{0}_{cell}}{RT}$

Substituting the given values into the above formula as follows.

ln K = $\frac{nFE^{0}_{cell}}{RT}$

= $\frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}$

ln K = -41.28

K = $e^{-41.28}$

= $1 \times 10^{-18}$

Thus, we can conclude that the value of the equilibrium constant for the given reaction is $1 \times 10^{-18}$ .

5 0

3 years ago

30. a. How do the properties of metals differ from those

Ahat [919]

Explanation:

Metals are elements that ionized by loss of electrons.

Ionic and molecular compounds are usually non-metals.

Properties of metals:

Metals have free mobile electrons and the metallic bonding ensures that.
They are usually electropositive and freely looses their electrons.
None of the metal is soluble without a chemical change occurring.
They are ductile and malleable.
Metals are good conductor or heat and electricity in their free uncombined state.
They are lustrous.

B. The specific property of metals accountable for their unusual electrical conductivity is due to the presence of free mobile electrons in their lattices.

learn more:

Metals brainly.com/question/2474874

#learnwithBrainly

3 0

3 years ago

From the formula MgO how do you know that Mg is the metal?

Damm [24]

In binary ionic compounds the name of the cation (Metal) is first, so that’s how you know.

5 0

2 years ago