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2 years ago

11

Briefly discuss why the use of general intelligence testing has declined in personnel selection.

1 answer:

vagabundo [1.1K]2 years ago

8 0

The use of general intelligence testing has declined in personnel selection because it is not the main stage for the selection.

<h3 /><h3>What is general intelligence?</h3>

General intelligence is a concept that consists of a variety of cognitive talents. These skills enable people to learn new things and solve issues.

This broad mental capacity underpins specialized mental talents in domains like spatial, numerical, mechanical, and linguistic abilities.

The existence of a wide mental capability that affects performance on cognitive ability measurements is referred to as general intelligence, often known as the g factor.

Other phrases used interchangeably to refer to broad intelligence include intelligence, IQ, general cognitive capacity, and general mental aptitude.

Hence, the use of general intelligence testing has declined in personnel selection because it is not the main stage for the selection.

<h3 />

To learn more about the general intelligence, refer to the link;

brainly.com/question/9944825

#SPJ1

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C: reflected

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3 years ago

A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads sh

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Answer:

Explanation:

Let the charge on bead A be q nC and the charge on bead B be 28nC - qnC

Force F between them

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3 years ago

Two long, parallel wires carry unequal currents in the same direction. The ratio of the currents is 3 to 1. The magnitude of the

astraxan [27]

Answer:

3A is the larger of the two currents.

Explanation:

Let the currents in the two wires be I₁ and I₂

given:

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Distance, R = 10cm = 0.1m

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Where $\mu_o$ is the magnitude constant = 4π×10⁻⁷ H/m

Thus, the magnitude of a magnetic field due to I₁ will be

$B_1 = \frac{\mu_oI_1}{2\pi R}$

$B_2 = \frac{\mu_oI_2}{2\pi R}$

given,

B = B₁ - B₂ (since both the currents are in the same direction and parallel)

substituting the values of B, B₁ and B₂

we get

4.0×10⁻⁶T = $\frac{\mu_oI_1}{2\pi R}$ - $\frac{\mu_oI_2}{2\pi R}$

or

4.0×10⁻⁶T = $\frac{\mu_o}{2\pi R}\times (I_1-I_2 )$

also

$\frac{I_1}{I_2} = \frac{3}{1}$

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also

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