Do you know how much water could you get if you started with 250.0 grams of hydrogen?
1 answer:
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Answer:
B.3/5p
Explanation:
For this question, we have to remember <u>"Dalton's Law of Partial Pressures"</u>. This law says that the pressure of the mixture would be equal to the sum of the partial pressure of each gas.
Additionally, we have a <em>proportional relationship between moles and pressure</em>. In other words, more moles indicate more pressure and vice-versa.
Where:
=Partial pressure
=Total pressure
=mole fraction
With this in mind, we can work with the moles of each compound if we want to analyze the pressure. With the molar mass of each compound we can calculate the moles:
<u>moles of hydrogen gas</u>
The molar mass of hydrogen gas () is 2 g/mol, so:
<u>moles of oxygen gas</u>
The molar mass of oxygen gas () is 32 g/mol, so:
Now, total moles are:
Total moles = 2 + 3 = 5
With this value, we can write the partial pressure expression for each gas:
So, the answer would be <u>3/5P</u>.
I hope it helps!
1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.
<h3>What is an ideal gas equation?</h3>The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 3.00 atm
V= ?
n=0.205 mole
R=
T=200 K
Putting value in the given equation:
V= 1.1214 mL
Learn more about the ideal gas here:
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