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Serga [27]
2 years ago
11

Do you know how much water could you get if you started with 250.0 grams of hydrogen?

Chemistry
1 answer:
Soloha48 [4]2 years ago
7 0

The amount of water that could we get if you started with 250.0 grams of hydrogen is 2,250 grams.

<h3>What is moles - mass realation?</h3>

Moles (n) and mass of any substance are related to each other according to the given equation as:

n = W/M, where

W = given mass

M = molar mass

Given balanced chemical reaction is:

2H₂ + O₂ → 2H₂O

Moles of 250g of H₂ = 250g / 2g/mol = 125mol

From the stoichiometry of the reaction it is clear that,

2 moles of H₂ = produces 2 moles of H₂O

125 moles of H₂ = produces 125 moles of H₂O

Now mass of water will be calculated as:

Mass = (125mol)(18g/mol) = 2,250g

Hence required mass of water is 2,250 grams.

To know more about moles & mass, visit the below link:
brainly.com/question/24631381

#SPJ1

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The complete question is shown in the image attached to this answer.

Answer:

C

Explanation:

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This equation states that;

E = E°cell - 0.592/n log Q

Where

E = EMF under non standard conditions

E°cell= standard EMF of the cell

n = number of electrons transferred

Q = reaction quotient

If the reaction quotient is greater than 1 then cell potential is less than the standard cell potential.

The cell that generates the lowest cell potential is the cell depicted in option C because Q has the greatest positive value(Q<1).

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What is the name of this molecule ?
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4 0
3 years ago
What is the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30c?
kap26 [50]
Use PV = nRT
(2 atm)(.3 liters) = n(8.314 mol*K)(303°K)

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3 0
3 years ago
Sucrose is very soluble in water. At 25◦C,
omeli [17]

Answer:

<h2>number of moles of solute dissolved in one liter of solution. </h2>

1. 8.28

Explanation:

I'm not sure but I hope it's help

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2 years ago
If 97.3 L of NO2 forms measured at 35 C and 632 mm Hg. What is the percent yield?
enyata [817]
<span>a. Use PV = nRT and solve for n = number of mols O2. 
mols NO = grams/molar mass = ? 

 Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR. 

b. 
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L. 

</span>and % will be 60%.
3 0
3 years ago
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