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Ivanshal [37]
3 years ago
11

A _____ is flat land that is higher than the land around it.

Chemistry
2 answers:
JulsSmile [24]3 years ago
6 0

Answer:b

Explanation:

Svetllana [295]3 years ago
4 0

Answer:

A

Explanation:

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The bond dissociation energy to break 4 bond(s) in 1 mole of CH₄ molecules is:_____ **Any help would be greatly appreciated!**
frozen [14]

Answer:

The bond dissociation energy to break 4 bonds in 1 mol of CH is 1644 kJ

Explanation:

Since there are 4 C-H bonds in CH₄, the bond dissociation energy of 1 mol of CH₄ is 4 × bond dissociation energy of one C-H bond.

From the table one mole is C-H bond requires 411 kJ, that is 411 kJ/mol. Therefore, 4 C-H bonds would require 4 × 411 kJ = 1644 kJ

So, the bond dissociation energy to break 4 bonds in 1 mol of CH₄ is 1644 kJ

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4 years ago
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Storage is the answer
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What is the other product for this reaction? Hbr + NaOH —&gt; ( select 2)
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*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: HBr + NaOH = nabr + h2o

Explanation:

I hope this helped!

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6 0
3 years ago
Need this ASAP!
AleksandrR [38]

Answer:

B. Lower than 100 °C because hydrogen sulfide has dipole-dipole interactions instead of hydrogen bonding.

Explanation:

Boiling point is a physical property which is usually a product of breaking intermolecular bonds.

Both dipole-dipole attractions are intermolecular bonds and they have serious effect on boiling point of a substance.

Hydrogen bonds are very strong intermolecular bonds compared to dipole-dipole attractions. In hydrogen bonding hydrogen atom is directly joined to a highly electronegative atom.

Dipole-Dipole attraction exists between molcules that are polar. Such molecules line up such that the positive pole of one molecule attracts the negative pole of another.

Hydrogen bonds in water are much stronger than the dipole-dipole attraction of hydrogen sulfide.

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3 years ago
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3 years ago
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