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2 years ago

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A _________ is a sample containing all components except analyte, and it is taken through all steps of the analytical procedure.

a. method blank b. reagent blank c. field blank d. spike blank e. matrix blank

1 answer:

Tatiana [17]2 years ago

4 0

Answer: Field bank

Explanation:

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If 0.500L solution weighs 596g and contains 90.0g of oxalis acid, the concentration can be expressed as ?M, or ?(m/m)%, or ?(m/v

irinina [24]

Answer : The concentration can be expressed as, 1.99 M, or 15.1(m/m)%, or 18(m/v)%

Solution : Given,

Volume of solution = 0.5 L = 500 ml (1 L = 1000 ml)

Mass of solution = 596 g

Mass of oxalic acid, (solute) = 90 g

Molar mass of oxalic acid = 90.03 g/mole

First we have to calculate the concentration in terms of M(molarity).

Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.

Formula used : $M=\frac{w_{solute}}{M_{solute}\times V_s}$

where,

M = molarity of solution

$w_{solute}$ = mass of solute(oxalic acid)

$M_{solute}$ = molar mass of solute(oxalic acid)

$V_s$ = volume of solution(in liters)

Now put all the given values in this formula, we get

$M=\frac{90g}{90.03g/mole\times 0.5L}=1.99mole/L=1.99M$

Now we have to calculate the concentration in terms of (m/m)%

(m/m)% : It is defined as the mass of solute present in mass of solution in grams.

Formula used : $(m/m)\%=\frac{w_{solute}}{w_s}\times 100$

where,

$w_s$ = mass of solution

$(m/m)\%=\frac{90g}{596g}\times 100=15.1%$

Now we have to calculate the concentration in terms of (m/v)%

(m/v)% : It is defined as the mass of solute present in one milliliter of solution.

Formula used : $(m/v)\%=\frac{w_{solute}}{V_s}\times 100$

where,

$w_s$ = mass of solution

$(m/m)\%=\frac{90g}{500ml}\times 100=18%$

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3 years ago

(a) calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 12.0 g. silver has 47 elect

Jet001 [13]

First calculate for number of moles:

moles Ag = 12 g / (107.87 g / mol)

moles Ag = 0.111 mol

Convert to atoms using Avogadros number:

atoms Ag = 0.111 mol * (6.022 x 10^23 atoms / mol)

atoms Ag = 6.7 x 10^22 atoms

There are 47 electrons per atom, therefore:

Number of electrons = (6.7 x 10^22 atoms) * (47 electrons / atom)

<span>Number of electrons = 3.15 x 10^24 electrons</span>

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John writes a definition for speed and time. Speed: Speed is the distance an object moves in an amount of time Time: The amount

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Answer:

A

Explanation:

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How many grams of CaF2 would be needed to produce 1.23 moles of F2?

NemiM [27]

We see from the chemical formula itself that there is 1 mole of F2 for every 1 mole of CaF2, hence the number of moles of CaF2 is also:

moles CaF2 = 1.23 moles

The molar mass of CaF2 is 78.07 g/mol, so the mass is:

mass CaF2 = 78.07 g / mol * 1.23 mol

<span>mass CaF2 = 96.03 grams</span>

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Explain the law of conservation of mass

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