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Helga [31]
3 years ago
6

What happens in a reduction half-reaction?

Chemistry
2 answers:
Marta_Voda [28]3 years ago
3 0
The answer is elements gain electrons. Oxidation reduction is elements lose electrons. And oxygen is added/lost can be a type of oxidation/reduction reaction.
Oksanka [162]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

A reduction-half reaction is defined as the reaction in which there occurs gain of one or more number of electrons by a specie or element.

Or, in a reduction-half reaction there occurs loss of oxygen if it is present in a reaction.

But in a reduction-half reaction loss of electrons will always take place.

For example, CuO + Mg \rightarrow Cu + MgO

Reduction-half reaction: Cu^{2+} + 2e^{-} \rightarrow Cu

So here, oxidation state of copper is changing from +2 to 0. Also, loss of oxygen is occurring in the reaction equation.

Oxidation-half reaction: Mg \rightarrow Mg^{2+} + 2e^{-}

Thus, we can conclude that in a reduction half-reaction elements gain electrons.

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arsen [322]

Answer:

92.65256 cm^3

Explanation:

To find this, we can simply multiply all three dimensions to get the answer in cubic centimeters, and we get the answer above. If you want to be more specific, we can go by the sigfig rule and the answer would be rounded to 93 cm^3.

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7 0
3 years ago
Calculate the second volumes 980L at 71C and 107.2atm to 13C and 59.3atm
Lapatulllka [165]

Answer:

V₂ = 1473.03 L

Explanation:

Given data:

Initial volume = 980 L

Initial pressure = 107.2 atm

Initial temperature = 71 °C (71 +273.15 = 344.15 K)

Final temperature = 13°C (13+273.15 = 286.15K)

Final volume = ?

Final pressure = 59.3 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 107.2 atm × 980L × 286.15 K / 344.15 K×   59.3 atm

V₂ = 30061774.4 atm .L. K / 20408.095 atm. K

V₂ = 1473.03 L

5 0
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