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Helga [31]
3 years ago
6

What happens in a reduction half-reaction?

Chemistry
2 answers:
Marta_Voda [28]3 years ago
3 0
The answer is elements gain electrons. Oxidation reduction is elements lose electrons. And oxygen is added/lost can be a type of oxidation/reduction reaction.
Oksanka [162]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

A reduction-half reaction is defined as the reaction in which there occurs gain of one or more number of electrons by a specie or element.

Or, in a reduction-half reaction there occurs loss of oxygen if it is present in a reaction.

But in a reduction-half reaction loss of electrons will always take place.

For example, CuO + Mg \rightarrow Cu + MgO

Reduction-half reaction: Cu^{2+} + 2e^{-} \rightarrow Cu

So here, oxidation state of copper is changing from +2 to 0. Also, loss of oxygen is occurring in the reaction equation.

Oxidation-half reaction: Mg \rightarrow Mg^{2+} + 2e^{-}

Thus, we can conclude that in a reduction half-reaction elements gain electrons.

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Describe the steps used to create Lewis dot structures to represent covalent bonds.
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Why is Hawaii made of volcanoes? <br>​
Vadim26 [7]

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8 0
2 years ago
How many chlorine atoms are there in 12.2 g of ccl4? How many chlorine atoms are there in 12.2 of ? 4.77×1022 atoms?
mash [69]

Answer:- 1.91*10^2^3Cl atoms.

Solution:- We have been given the grams of carbon tetrachloride and asked to calculate the number of atoms of chlorine. It is a three step conversion problem. In the first we convert the grams of carbon tetrachloride to moles of it. In second step we convert moles of carbon tetrachloride to moles of chlorine and in the third step we convert the moles of chlorine to atoms of chlorine.

For grams to mole conversion we need the molar mass of the compound. Molar mass of carbon tetrachloride is 153.82 grams per mol. If we look at the formula of carbon tetrachloride then four chlorine are present in it. It means 1 mol of carbon tetrachloride has four moles of chlorine. The calculations are as follows:

12.2gCCl_4(\frac{1molCCl_4}{153.82gCCl_4})(\frac{4molCl}{1molCCl_4})(\frac{6.02*10^2^3Clatoms}{1molCl})

= 1.91*10^2^3Cl atoms

So, there are 1.91*10^2^3Cl atoms in 12.2 grams of CCl_4 .

6 0
3 years ago
Read 2 more answers
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