The mass of butane gas at the given volume and Standard temperature and pressure is 0.0022g.
<h3>What is Ideal Gas Law?</h3>
The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.
It is expressed as;
PV = nRT
Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )
Given the data in the question;
- Volume of the gas V = 3L
- At STP; P = 1.0atm, T = 273.15K
- Amount of gas n = ?
PV = nRT
n = PV / RT
n = ( 1.0atm × 3.00L ) / ( 0.08206 Latm/molK × 273.15K )
n = 3.00Latm / 22.41 Latm/mol
n = 0.13mol
Now, since Molar mass of brutane gas is 58.12 g/mol.
Mass = n × Molar mass
Mass = 0.13mol × 58.12 g/mol
Mass = 0.0022g
Therefore, the mass of butane gas at the given volume and Standard temperature and pressure is 0.0022g.
Learn more about Ideal Gas Law here: brainly.com/question/4147359
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