1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hoa [83]
3 years ago
12

(2 x 109) x (5 x 105).

Chemistry
2 answers:
Finger [1]3 years ago
8 0

Answer:

114450

Explanation:

2*109 = 218

5*105 = 525

218*525 = 114450

MA_775_DIABLO [31]3 years ago
8 0
Simplify the expression.
114450
You might be interested in
Calculate the standard free-energy change at 25 ∘C for the following reaction:
lianna [129]

Answer:

Standard free-energy change at 25^{0}\textrm{C} is -3.80\times 10^{2}kJ/mol

Explanation:

Oxidation: Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)

Reduction: Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)

--------------------------------------------------------------------------------------

Overall: Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)

Standard cell potential, E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}

So, E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V

We know, standard free energy change at 25^{0}\textrm{C}(\Delta G^{0}): \Delta G^{0}=-nFE_{cell}^{0}

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, \Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol

8 0
3 years ago
Read 2 more answers
In h2o, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a
Murrr4er [49]
The hydrogen and oxygen<span> atoms from H</span>₂O are <span>bonded together through covalent </span>bonding. 
3 0
3 years ago
Mercury is a liquid metal having a density of 13.6 gml what is the volume of 1.00 lb of mercury metal
tresset_1 [31]

The volume of 1.00 lb of mercury metal : 33.352 ml

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

Density of metal(mercury) = 13.6 g/ml

mass of mercury : 1 lb = 453,592 g

So the volume :

\tt V=\dfrac{453,592~g}{13.6~g/ml}\\\\V=33.352~ml

7 0
3 years ago
Can you substitute evaporated milk for condensed milk
alex41 [277]
Yes because condensed milk and evaporated milk are similar to one another. However, there won’t be the same sweet flavor but the texture is the same.
3 0
3 years ago
What is the molar mass of CaCl2?
Aleks04 [339]

Answer: The molar mass of the given compound is 1.11\times 10^2 g/mol

Explanation:

In molecular formula of CaCl_2 there are two chlorine atoms and one calcium atom.

The atomic mass of the calcium = 40.07 g/mol

The atomic mass of chlorine = 35.5 g/mol

Molar mass of the guven compound is :

40.07 g/mol + 2\times 35.5 g/mol=111.07 g/mol\approx 1.11\times 10^2 g/mol

The molar mass of the given compound is 1.11\times 10^2 g/mol

8 0
3 years ago
Other questions:
  • Name the following organic compounds.
    5·1 answer
  • What is 0.0135 moles of in AlCl3 grams? Round to 3 sig figs
    10·1 answer
  • What is the ph of a 0.45 m solution of aniline (c6h5nh2)? (pkb  9.40)?
    14·1 answer
  • How is<br> solid different from gas ?
    9·2 answers
  • A liquid has_____volume and a _____ shape.
    12·1 answer
  • can someone make me a lab report? Please......... Objective(s): In your own words, what was the purpose of this lab? Hypothesis:
    14·2 answers
  • An experiment was preformed to test the effects of different types of fertilizers on the number of tomatoes produced by one type
    15·1 answer
  • How many valence electrons does an atom of Iodine have?<br><br> a) 5 <br> b) 6 <br> c) 7 <br> d) 8
    6·2 answers
  • A penny is 0.061 inches thick. What is the value of the 6 in the thickness of a penny? Mathematics not chemistry
    11·2 answers
  • Select the correct answer.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!