(2 x 109) x (5 x 105).
2 answers:
You might be interested in
Answer:
The answer is -297 kJ
Explanation:
The enthalpy change is state function and can be calculated from Hess' s Law
The two reactions can be combined to obtain the third equation to calculate its enthalpy change as the enthalpy change depends upon only the initial and final state irrespective of path taken.
(1) ...... ΔH° = 66.4 kJ
(2) ......ΔH° = -164.2 kJ
The required equation is:
(3) ......ΔH° = _________?
We will multiply the equation (1) with "2" and then will subtract it from equation "1"
(2) ......ΔH° = -164.2 kJ
-2[X(1) ...... ΔH° = 66.4 kJ
]
......................................................................................................................................
ΔH° = ΔH°(eq 2) - 2ΔH°(eq 1) = -164.2 -(2X66.4) = -297 kJ