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3 years ago

How much heat is required to change the temperature of 100 grams of water from 25 to 55oc?

1 answer:

5 0

Hthe heat required to change the temperfature of 100 grams of water from 25 to 55 c is calculated as below

Q(heat) = M(mass) x C(specific heat capacity) x delta T(change in temperature)

M= 100 grams
C= 4.18 j/g/c
delta T= 55-25 =30c

Q=100 g x4.814 j/g/c x 30c = 12552 joules

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Consider the following system at equilibrium where H° = 111 kJ/mol, and Kc = 6.30, at 723 K.

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1) The value of Kc:

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4 years ago

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nika2105 [10]

<h3>Answer:</h3>

0.0253 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.456 g H₂O (water)

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.025305 \ mol \ H_2O$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.025305 mol H₂O ≈ 0.0253 mol H₂O

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