6-a).
Force = (mass) x (acceleration)
Net force on the trolley = (20 kg) · (0.5 m/s²) =
Net force on the trolley = 10 Newtons.
6-b).
But you're pushing it with 15N of force.
Something mysterious is fighting your force, and
pushing the trolley BACKWARDS with 5N of force.
THAT's the effect of friction.
7-a).
F = (mass) x (acceleration)
Divide each side by (mass):
Acceleration = (force) / (mass)
For the car,
Acceleration = (-5,000 Newtons) / (1,000 kg)
Acceleration = -5 m/s² .
7-b).
change in velocity= acceleration x time
change = (-20 m/s)
-20 m/s = (-5 m/s²) · (time)
Divide each side by (-5 m/s²) :
Time = (-20 m/s) / (-5 m/s²)
Time = 4 seconds .
Answer:
the angle, in radians, between the central maximum = 2.87degree or 0.05radians
Explanation:
The detailed steps and appropriate formula is as shown in the attachment.
Using λm = dsin teta
where d =20λ, m = 1
from the formula, sin teta = λ/20λ
= sin teta = 0.05
teta = arc sin(0.05) = 2.87 degree
A uniform thin solid door has height 2.20 m, width .870 m, and mass 23.0 kg. Find its moment of inertia for rotation on its hinges. Is any piece of data unnecessary? So far, I don't understand how to calculate moments of inertia for things like this at all. I can do a system of particles, but when it comes to any ridgid objects, such as this door or rods or cylinders, I don't get it. So basically I have no idea where to even start with this.
so A
Speed and velocity are both measured using the same units. The SI unit of distance and displacement is the meter. The SI unit of time is the second. The SI unit of speed and velocity is the ratio of two — the meter per second.
Source: https://physics.info/velocity/
Hope it helps!
To solve the problem, it will be necessary to define the rotational and translational kinetic energy in order to determine the relationship between the two. Rotational energy is defined as,
Here,
I = Moment of Inertia
= Angular velocity
Now the translational energy will be,
Here,
m = Mass
v = Velocity
Therefore the relation between them will be,
Applying the moment of inertia of a sphere we have,
Therefore the ratio will be 0.01077