Question

What is the OH- in a solution with a pOH of 7.68?

Answer 1

Answer:

Explanation:

Answer: 1.380 × 10^-8 M

The pH is the measure of alkalinity or acidity of a substance.

It is the negative logarithm of H+ ions concentration [H+].

pH = -log[H+]

pOH on the other hand is negative logarith of OH- concentration [OH-].

pOH = -log[OH-]

In this case;

pOH = 7.86

We can calculate the [OH-]

pOH = -log[OH-]

But, pOH = 7.86

pOH = -log[OH-]

-log[OH-] = 7.86

[OH-] = Antilog -7.86

      = 1.380 × 10^-8 M

Therefore, [OH-] is 1.380 × 10^-8 M