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vivado [14]
2 years ago
8

Carla draws two circuit diagrams that connect the same components in different ways, as shown. which statement about the circuit

s is correct? the total resistance in circuit a is greater than that in circuit b. when a bulb in circuit a goes out, the other bulbs keep shining. the bulbs in circuit a shine brighter than those in circuit b. when a bulb in circuit b goes out, the other bulbs go out.
Physics
1 answer:
vagabundo [1.1K]2 years ago
5 0

Carla draws two circuit diagrams that connect the same components in different ways, as shown. The correct statement is "the total resistance in circuit a is greater than that in-circuit b.". Option A. This is further explained below.

<h3>What is a circuit?</h3>

Generally, a circuit is simply defined as a fixed schedule of activities or places for a certain activity, usually including athletics or public performance.

In conclusion, Carla creates two circuit schematics, as illustrated, that link the same components in various ways. "The overall resistance in circuit an is larger than that in b," is the correct statement.

Read more about  resistance

brainly.com/question/11431009

#SPJ4

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The sun?? It stays in one spot, but from our point of view, it travels around the earth...
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A wheel initially spinning at wo = 50.0 rad/s comes to a halt in 20.0 seconds. Determine the constant angular acceleration and t
svetlana [45]

Answer:

(I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.

(II). The torque is 84.87 N-m.

Explanation:

Given that,

Initial spinning = 50.0 rad/s

Time = 20.0

Distance = 2.5 m

Mass of pole = 4 kg

Angle = 60°

We need to calculate the angular acceleration

Using formula of angular velocity

\omega=-\alpha t

\alpha=-\dfrac{\omega}{t}

\alpha=-\dfrac{50.0}{20.0}

\alpha=-2.5\ rad/s^2

The angular acceleration is -2.5 rad/s²

We need to calculate the number of revolution

Using angular equation of motion

\theta=\omega_{0}t+\dfrac{1}{2}\alpha t

Put the value into the formula

\theta=50\times20-\dfrac{1}{2}\times2.5\times20^2

\theta=500\ rad

The number of revolution is 500 rad.

(II). We need to calculate the torque

Using formula of torque

\vec{\tau}=\vec{r}\times\vec{f}

\tau=r\times f\sin\theta

Put the value into the formula

\tau=2.5\times4\times 9.8\sin60

\tau=84.87\ N-m

Hence, (I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.

(II). The torque is 84.87 N-m.

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As

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where ∅ = 90° is the angle between between radius vector r  and angular velocity w (omega )

In case ∅ ≠ 90° , we can write v = r w sin∅

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3 years ago
A block is released from rest, at a height h, and allowed to slide down an inclined plane. There is friction on the plane. At th
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Here the block has two work done on it

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So here it start from height "h" and then again raise to height hA after compressing the spring

So work done by the gravity is given as

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Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path

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So answer will be

None of these

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3 years ago
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