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postnew [5]
3 years ago
8

Large vehicles need more room to make turns. when you approach an intersection and see a truck ahead signaling a right turn, you

should stay next to the truck, close to the curbside, until the turn is completed.
Physics
1 answer:
netineya [11]3 years ago
4 0
This statement is false.
The correct statement would be,
"W<span>hen you approach an intersection and see a truck ahead signaling a right turn, you should stay behind the truck, away from the curbside, until the turn is completed."

Larger vehicles require a larger space to turn, being next to the truck and close to the curbside will only make it more difficult for the truck driver to complete the turn. This in turn will waste more time or even block traffic while the truck driver tries to complete the turn in the difficult situation that could have easily been avoided.</span>

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Why scientists collect data about the moon?
Strike441 [17]

Explanation:

Scientists collect data for decades after Apollo 11's return to earth. Finding include that the moon is moving farther away from earth and that the universal force of gravity is stable.

6 0
3 years ago
PLEASE HELP!!!!!!! MY HOMEWORK IS DUE TODAY !!!!!!!!
bogdanovich [222]

Answer:

Distance = 25000000 miles

Time = 50 hours

Explanation:

Venus is the closest planet to Earth. It is about 25 million miles away from Earth. Its precise distance depends on where both Venus and Earth are in their respective orbits

Given that

Speed V = 500000 mph

Distance d = 25 000,000 miles

Speed = distance/ time

Time = distance/speed

Time = 25000000/500000

Time = 50 hours

It will therefore take 50 hours to get to venus at that speed.

5 0
3 years ago
Suppose that the electric field in the Earth's atmosphere is E = 8.60 101 N/C, pointing downward. Determine the electric charge
asambeis [7]

Answer:

q = 3.87 x 10⁵ C

Explanation:

given,

Electric field, E = 8.60 x 10¹ = 86 N/C

radius of earth, R = 6371 Km = 6.371 x 10⁶ m

Coulomb constant, K = 9 x 10⁹ N · m²/C²

Charge on the earth = ?

the electric field at the point

E =\dfrac{kq}{r^2}

q =\dfrac{Er^2}{k}

inserting all the values

q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}

      q = 3.87 x 10⁵ C

The electric charge on the earth is equal to 3.87 x 10⁵ C

4 0
3 years ago
How fast would you be going (in kmh) if you had a ship that accelerated at a constant 1g for 24 hours?
Nady [450]

Answer:

Explanation:

1 g is 9.8 m/s^2 the problem wants the results in km/h so we'll fix that really quick.

9.8 m/s^2 (1 km/1000m)(60 sec/1 min)^2(60 min/1 hour)^2 = 127008 km/hour^2

Now, I'm assuming the ship is starting from rest, and hopefully you know your physics equations.  We are going to use vf = vi + at.  Everything is just given, or we can assume, so I'll just solve.

vf = vi + at

vf = 0 + 127008 km/hour^2 * 24 hours

vf = 3,048,192 km/hour

If there's anything that doesn't make sense let me know.  

5 0
3 years ago
1. Calculate the height of tree, 250 m away that produces
gtnhenbr [62]

Answer:

Explanation:

1.5/30 = x/250

x = 12.5 m

5 0
2 years ago
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