In 1949, dr. tony allison observed a high frequency of kenyans carrying the sickle cell allele in coastal areas and near lake vi
1 answer:
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Answer:
E=15.3*10¹³ N/C : approximate
Explanation:
We use the following formula to calculate the electric field due to a disk with uniform surface charge at a point P that is along the central perpendicular axis of the disk and at a distance x from the center of the disk:
E= 2*π*k*σ*F Fórmula ( 1 )
E: Electric field at point P (N/C)
σ: surface charge density (C/m²)
R: disk radio (m)
x :distance from the center of the disk to the point P located on the axis of the disk (m)
K: Coulomb constant ( N*m²/C)
Equivalences
1cm = 10⁻²m
1mm = 10⁻³m
Data
R =2.6 cm= 2.6*10⁻²m = 0.026m
x=3.7 mm = 3.7* 10⁻³m = 0,0037 m
Q=+6.71C.
k= 8.98774 * 10⁹ N* m²/C
Calculation of surface charge density (σ )
σ= Q/A
Q: uniformly distributed charge (C)
A: disk area (m²) = π*R²
σ= +6.71C/π*(2.6*10⁻²)²m² = 3159.56C/m²
Calculation of the electric field at point P
We apply formula (1) and replace data
E= 2*π*3159.56*8.98774*10⁹ *F
E=15.3*10¹³ N/C : approximate
Answer:
v=1.5081 m/s
Explanation:
<u>Uniform Circular Motion </u>
The cork is performing a circular motion which we assume to be uniform (constant angular speed or angular acceleration zero)
The centripetal force applied to it is given by
where m is the mass and is the centripetal acceleration. This acceleration appears since the tangent speed is constantly changing direction. If w is the angular speed and r is the radius of rotation
The speed of the cork can be found with the formula
We can compute w since we know the rotation period <em>T=1.25 sec </em>
Now, since r=0.30 m, let's compute v
And finally