Answer is: <span>it comes at the right time.
Some of the chemistry discoveries that come in right time (with enough informations, knowledge and right technology to use that discovery) are: </span>Periodic Table of the Elements, discovery of electron, proton, neutron, radioactivity, pasteurization, t<span>he Haber-Bosch process.</span>
Zn = 28.15%
Cl = 30.53%
O = 41.32%
<h3>Further explanation</h3>
Given
Zn(CIO3)2 compound
Required
The % composition
Solution
Ar Zn = 65.38
Ar Cl = 35,453
Ar O = 15,999
MW Zn(CIO3)2 = 232.3
Zn = 65,38/232.3 x 100% = 28.15%
Cl = (2 x 35.453) / 232.3 x 100% = 30.53%
O = (6 x 15.999) / 232.3 x 100% = 41.32%
Plastic pollution is the correct answer
Answer:
0.00370 g
Explanation:
From the given information:
To determine the amount of acid remaining using the formula:![\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n](https://tex.z-dn.net/?f=%5Cdfrac%7B%28final%20%5C%20mass%20%5C%20of%20%5C%20solute%29_%7Bwater%7D%7D%7B%28initial%20%5C%20mass%20%5C%20of%20%5C%20solute%20%29_%7Bwater%7D%7D%20%3D%20%28%5Cdfrac%7Bv_2%7D%7Bv_1%2Bv_2%5Ctimes%20k_d%7D%29%5En)
where;
v_1 = volume of organic solvent = 20-mL
n = numbers of extractions = 4
v_2 = actual volume of water = 100-mL
k_d = distribution coefficient = 10
∴
![\dfrac{(final \ mass \ of \ solute)_{water}}{0.30 \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4](https://tex.z-dn.net/?f=%5Cdfrac%7B%28final%20%5C%20mass%20%5C%20of%20%5C%20solute%29_%7Bwater%7D%7D%7B0.30%20%20%5C%20g%7D%20%3D%20%28%5Cdfrac%7B100%20%5C%20ml%7D%7B100%20%5C%20ml%20%2B20%20%5C%20ml%20%5Ctimes%2010%7D%29%5E4)
![\dfrac{(final \ mass \ of \ solute)_{water}}{0.30 \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4](https://tex.z-dn.net/?f=%5Cdfrac%7B%28final%20%5C%20mass%20%5C%20of%20%5C%20solute%29_%7Bwater%7D%7D%7B0.30%20%20%5C%20g%7D%20%3D%20%28%5Cdfrac%7B100%20%5C%20ml%7D%7B100%20%5C%20ml%20%2B200%20%5C%20ml%7D%29%5E4)
![\dfrac{(final \ mass \ of \ solute)_{water}}{0.30 \ g} = (\dfrac{1}{3})^4](https://tex.z-dn.net/?f=%5Cdfrac%7B%28final%20%5C%20mass%20%5C%20of%20%5C%20solute%29_%7Bwater%7D%7D%7B0.30%20%20%5C%20g%7D%20%3D%20%28%5Cdfrac%7B1%7D%7B3%7D%29%5E4)
![\dfrac{(final \ mass \ of \ solute)_{water}}{0.30 \ g} = 0.012345](https://tex.z-dn.net/?f=%5Cdfrac%7B%28final%20%5C%20mass%20%5C%20of%20%5C%20solute%29_%7Bwater%7D%7D%7B0.30%20%20%5C%20g%7D%20%3D%200.012345)
Thus, the final amount of acid left in the water = 0.012345 * 0.30
= 0.00370 g