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Harrizon [31]
3 years ago
12

For the following reaction, 7.72 grams of nitrogen gas are allowed to react with 4.86 grams of oxygen gas . nitrogen(g) oxygen(g

) nitrogen monoxide(g) What is the maximum mass of nitrogen monoxide that can be formed
Chemistry
1 answer:
inn [45]3 years ago
7 0
There could be a big maximum amount or small, either works
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What elements are most commonly used in wiring?
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Answer:

Hi myself Shrushtee.

Explanation:

Wire Materials: The most common material for electrical wire is copper and aluminum, these are not the best conductors however they are abundant and low cost. Gold is also used in applications because it is corrosion resistant.

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Number 58!! PLEASE EXPLAIN!!! And show work
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3 years ago
2 moles of a gas have a pressure of 2 atm at a temperature of 300 K. What is the volume of the gas?
qwelly [4]
  • No of moles=2mol=n
  • Pressure=2atm=P
  • Temperature=300K=T
  • Volume=V

\\ \tt\hookrightarrow PV=nRT

\\ \tt\hookrightarrow V=\dfrac{nRT}{P}

\\ \tt\hookrightarrow V=\dfrac{2(8.314)(300)}{2}

\\ \tt\hookrightarrow V=8.314(300)

\\ \tt\hookrightarrow V=2494.2mL

\\ \tt\hookrightarrow V=24.94dm^3

4 0
2 years ago
3. At a pressure of 405 kPa, the volume of a gas is 6.00 cm
monitta

The pressure gets increased to 486 kPa from 405 kPa, when the volume is decreased from 6 cm³ to 4 cm³.

Explanation:

In the present problem, the temperature is said to remain at constant and there is change in the pressure. So according to Boyle's law, the relationship between pressure and volume of any gaseous objects are inversely related to each other. In other words, the pressure attained by gas molecules in a container will be inversely proportional to the volume of the gas molecules occupied in the container, at constant temperature.

V=\frac{1}{P}

So, if two volumes V₁ and V₂ are considered, then their respective pressure will be represented as P₁ and P₂. Then, as per Boyle's law,

V_{1}P_{1}=V_{2}P_{2}

So let us consider, V₁ = 6 cm³ and V₂ = 4 cm³ and pressure P₁ = 405 kPa and we have to determine P₂.

Then,  6*405=5*P_{2}\\ \\P_{2}=\frac{2430}{5} =486 kPa

So, the pressure at new volume of 4 cm³ is 486 kPa. It can be seen that as there is decrease in the volume, there is an increase in the pressure. So it satisfied the Boyle's law.

Thus, the pressure gets increased to 486 kPa from 405 kPa, when the volume is decreased from 6 cm³ to 4 cm³.

6 0
3 years ago
Type the temperatures in Kelvin) in the left column
docker41 [41]

Answer: the data appear to be ( linear )

The line of best fit is v= 0.003 t+ 0.003

Notice the the value of the v intercept is close to 0 so V and t are ( directly proportional)

8 0
3 years ago
Read 2 more answers
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