2.15 x 10⁻³mL
Explanation:
Given parameter:
Volume of blood sample in uL = 2.15uL
Conversion uL → mL
micro- and milli- are both prefixes of sub-units.
liter is a unit of volume of a substance.
micro - is 10⁻⁶
milli- is of the order 10⁻³
The problem is converting from micro to milli:
if we multiply 10⁻⁶ by 10³ we would have our milli;
1000uL = 1mL
2.15uL : 2.15uL x = 2.15 x 10⁻³mL
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Answer:
Explanation:
Assume you are using 1 L of water.
Then you are washing 4 L of salty oil.
1. Calculate the mass of the salty oil
Assume the oil has a density of 0.86 g/mL.
2. Calculate the mass of salt in the salty oil
3. Calculate the mass of salt in the spent water
4. Mass of salt remaining in washed oil
Mass = 172 g - 150 g = 22 g
5. Concentration of salt in washed oil
Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ
Explanation :
First we have to calculate the moles of n-butane.
Given:
Molar mass of n-butane = 58.12 g/mole
Mass of n-butane = 58.3 g
Now put all the given values in the above expression, we get:
Now we have to calculate the energy required.
where,
Q = energy required
= enthalpy of fusion of solid n-butane = 4.66 kJ/mol
n = moles = 1.00 mol
Now put all the given values in the above expression, we get:
Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ