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babunello [35]
3 years ago
10

Thats the guide to the project , someone help please 20 points

Chemistry
2 answers:
Alexus [3.1K]3 years ago
5 0

Answer:

sorry plz i do needz   20 pts

Explanation:

Fittoniya [83]3 years ago
4 0

Answer:

do you want the whole project or just a part of it done ?

Explanation:

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dating and correlating the strata in which it is found

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Use the periodic table to choose the correct name for each of the following substances. Check all tha
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List the three requirements for a correctly written chemical equation.2. Give one example of a word equation, one example of a f
erma4kov [3.2K]

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Requirements for a correctly written chemical equation are reactants and products, their formula and valency

Explanation:

Formula of the given compound are -

1 - Potassium Hydroxide - KOH

2 - Calcium Nitrate - Ca(NO_3)_2

The requirements for a correctly written chemical equation are -

  • Identifying reactants and products
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Example of word equation, formula equation, and chemical equation is as follows -

Aluminium + iron9(III)oxide ⇒ aluminium oxide + iron (word equation)

Al_(_s_)  + Fe_2O_3_(_s_)    ⇒   Al_2O_3_(_s_)  + Fe_(s) (formula equation)              

2Al_(_s_) + Fe_2O_3_(_s_)    ⇒   Al_2O_3_(_s_)   + 2Fe_(_s_) (chemical equation)

8 0
3 years ago
A more reactive metal displaces a less reactive metal from salt solution. Such reactions are called:
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6 0
3 years ago
Read 2 more answers
Is 13.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Andrews [41]
Answer: 
 Zn =⇒ Zn+2(0.10) + 2e- (anode)
 Zn+2(?M) + 2e- === Zn(s) (cathode)
 
 Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn 
 E = E^o -0.0592 log Q; in this case E^o is zero. 
 E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2 
 23 mV x 1 volt/1000mv = 0.023 Volts 
 0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
 0.023 = -0.0296 { log 0.10 – log [Zn+2] }
 0.023 = -0.0296{ -1 - log[Zn+2] }
 0.023 = +0.0296 + 0.0296log[Zn+2]
 -0.0066 = 0.0296log[Zn+2]
 -0.22= log[Zn+2]
 [Zn+2] = 10^-0.22 = 0.603 Molar

6 0
3 years ago
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