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babunello [35]
3 years ago
10

Thats the guide to the project , someone help please 20 points

Chemistry
2 answers:
Alexus [3.1K]3 years ago
5 0

Answer:

sorry plz i do needz   20 pts

Explanation:

Fittoniya [83]3 years ago
4 0

Answer:

do you want the whole project or just a part of it done ?

Explanation:

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A technician measures the weight of a reagent . The weight is 3269 g. What is the weight in kilograms ? Write your answer as a d
Georgia [21]

Answer:

3.269 kg

Explanation:

1000g = 1 kg. Since kg is the larger unit, you need to divide by 1000 to get kilograms. You can do the problem as a unit conversion:

3269 g × <u>1 kg</u>  =  3.269 kg

                1000g

Hope this is helpful!

5 0
3 years ago
The clouds of Venus consist mainly of ______. Group of answer choices carbon monoxide droplets of water vapor hydrogen and heliu
Zanzabum

Answer:

droplets of sulfuric acid

Explanation:

4 0
3 years ago
Sibling rivalry may occur when:
sweet [91]

Answer:

Explanation: true

7 0
3 years ago
A helium balloon is filled on the ground where the atmospheric pressure is 768 torr. The volume of the balloon is 8.00 m3. When
Anvisha [2.4K]

Answer:

The correct option is: <u>B. 366 torr</u>

Explanation:

Given: <u>On the ground</u>- Initial Volume: V₁ = 8.00 m³, Initial Atmospheric Pressure: P₁= 768 torr;

<u>At 4200 m height</u>- Final Volume: V₂ = 16.80 m³, Final Atmospheric Pressure: P₂ = ?

Amount of gas: n, and Temperature: T = constant

<u>According to the Boyle's Law</u>, for a given amount of gas at constant temperature:         P₁ V₁ = P₂ V₂

⇒  P₂ = P₁ V₁ ÷ V₂

⇒  P₂ = [(768 torr) × (8.00 m³)] ÷ (16.80 m³)

⇒  P₂ = 365.71 torr ≈ 366 torr

<u>Therefore, the final air pressure at 4200 m height: P₂ = 366 torr.</u>

6 0
3 years ago
I am finding the formula of a compound that has 60% Carbon, 32% Oxygen, and 8% Hydrogen. Although, when it comes to actually cre
nataly862011 [7]

Answer:

Explanation:

To determine the molecular formula of the compound, the empirical formula must be determined first. To determine the empirical formula, the percentage of each constituent is divided by its molar mass. This is shown below

Carbon = 60/12 = 5

Oxygen = 32/16 = 2

Hydrogen = 8/1 = 8

The next step is to divide each ratio by the smallest value. The smallest value is 2. It becomes

Carbon = 5/2 = 2.5

It is approximated to 3

Oxygen = 2/2 = 1

Hydrogen = 8/2 = 4

Therefore, the empirical formula is

C3H4O

From the given relative molecular mass of the compound, the molecular formula can be determined

7 0
3 years ago
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