The new volume of gas Y is 89.38 mL
From the question given above, the following data were obtained:
Initial volume (V₁) = 82.0 mL
Initial temperature (T₁) = 27.0 °C = 27 + 273 = 300 K
Final temperature (T₂) = 54.0 °C = 54 + 273 = 327 K
Pressure = 3 atm = constant
<h3>Final volume (V₂) =? </h3>
Since the pressure is constant, we shall determine the final volume of gas Y using the Charles' law equation as follow:
Cross multiply
300 × V₂ = 82 × 327
300 × V₂ = 26814
Divide both side by 300
<h3>V₂ = 89.38 mL</h3>
Therefore, the new volume of gas Y is 89.38 mL
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Answer : The standard enthalpy of formation of methane is, -74.8 kJ/mole
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
Now we will reverse the reaction 1, multiply reaction 3 by 2 then adding all the equations, we get :
(1) 
(2)
(3) 
The expression for enthalpy of formation of will be,
Therefore, the standard enthalpy of formation of methane is, -74.8 kJ/mole
D would be correct (i did this Assessment today)<span />
Answer:
The metal which is liquid in room temperature is mercury
They tend to pick at it until it is in small enough pieces to swallow. Then their gizzard (rough muscle) in their stomach acts as internal teeth.
