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2 years ago

2c8h18(g 25o2(g→16co2(g 18h2o(g how many moles of water are produced in this reaction

Chemistry

2 answers:

Whitepunk [10]2 years ago

5 0

<u>Answer:</u> The amount of water produced is 18 moles.

<u>Explanation:</u>

The given chemical reaction follows:

$2C_8H_{18}(g)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)$

By Stoichiometry of the reaction:

2 moles of octane gas reacts with 25 moles of oxygen gas to produce 16 moles of carbon dioxide gas and 18 moles of water molecule.

Number of water molecules produced = 18 moles

Hence, the amount of water produced is 18 moles.

AleksandrR [38]2 years ago

3 0

18 moles of water are produced in the above reaction.
Hope this helps you!

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Svetradugi [14.3K]

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3 years ago

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2 years ago

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3 years ago

In a reaction of a potential new fuel, it is found that when 2.81 moles of the fuel combusts, 1,612 kJ of energy is released. Wh

Tema [17]

Answer:

-573.67

Explanation:

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2 years ago

If the half-life of Carbon-14 is 5700 years, how many years would it take a sample to decay from 1 gram to 31.3 mg

andrew-mc [135]

Answer:

28500 years

Explanation:

Applying,

A = A'( $2^{x/y}$ )............... Equation 1

Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.

From the question,

Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.

Substitute these values into equation 1

1 = 0.0313( $2^{x/5700}$ )

$2^{x/5700}$ = 1/0.0313

$2^{x/5700}$ = 31.95

$2^{x/5700}$ ≈ 32

$2^{x/5700}$ ≈ 2⁵

Equating the base and solve for x

x/5700 ≈ 5

x ≈ 5×5700

x ≈ 28500 years

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2 years ago