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Vadim26 [7]
2 years ago
10

2c8h18(g 25o2(g→16co2(g 18h2o(g how many moles of water are produced in this reaction

Chemistry
2 answers:
Whitepunk [10]2 years ago
5 0

<u>Answer:</u> The amount of water produced is 18 moles.

<u>Explanation:</u>

The given chemical reaction follows:

2C_8H_{18}(g)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)

By Stoichiometry of the reaction:

2 moles of octane gas reacts with 25 moles of oxygen gas to produce 16 moles of carbon dioxide gas and 18 moles of water molecule.

Number of water molecules produced = 18 moles

Hence, the amount of water produced is 18 moles.

AleksandrR [38]2 years ago
3 0
18 moles of water are produced in the above reaction.
Hope this helps you!
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Limes and lemons have a ph of 2 and are acidic.
3 0
3 years ago
A buffer is 0.282 m c6h5cooh(aq and 0.282 m na(c6h5coo(aq. calculate the ph after the addition of 0.150 moles of nitric acid to
Sindrei [870]
You have to use the Henderson-Hasselbalch equation. Keep in mind that because the Pka is given the equation changes form slightly:

PH = Pka + log[acid/base]

Step 1 (Figure out the concentrations):

0.282 M of Acid (C6H5OOH) - 0.150 M = 0.132 M of acid
0.282 M of Base (C6HCOO) + 0.150 M = 0.432 M of bas3

Step 2 (Plug into equation):

PH = Pka + log[acid/base]
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7 0
3 years ago
4. How many moles of gold (Au) are in a pure gold nugget having a mass of 25.0 grams.
ikadub [295]
<h3>Answer:</h3>

0.127 mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 25.0 g Au

[Solve] moles Au

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 25.0 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. [DA] Multiply/Divide [Cancel out units:                                                          \displaystyle 0.126923 \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.126923 mol Au ≈ 0.127 mol Au

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2 years ago
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Answer:

A. The rate of heat transfer through the material would increase.

Explanation:

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5 0
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