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2 years ago

Which end of an earthworm contains an organ that can detect smells? Use observations from the lab to support your answer.

Chemistry

1 answer:

Elena L [17]2 years ago

3 0

The anterior which is the front of the earth worm can detect smell due to the organ prostomium

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Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of microgra

leonid [27]

Answer:

0.125 mg

Explanation:

<em>The correct answer would be 0.125 mg</em>

<u>According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.</u>

milligram = $10^{-3}$

microgram = $10^{-6}$

Hence,

1 milligram = 1000 micrograms or 1 microgram = $10^{-3}$ milligram

Therefore, 125 micrograms will be:

125/1000 = 0.125 milligram

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3 years ago

What human actions increase the amount of carbon dioxide?

kati45 [8]

The burning of oil, coal, and gas

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3 years ago

Which situation shows a nonrenewable resource in use?

miv72 [106K]

Answer:

Explanation:

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1 year ago

Which of the following weather conditions might result in a hurricane?

natima [27]

Hurricanes always originate over oceans. The correct answer is choice C.

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2 years ago

Read 2 more answers

Baking soda (sodium bicarbonate) is often used to neutralize spills of acids on the benchtop of the laboratory. What mass of sod

FrozenT [24]

Answer : The mass of $NaHCO_3$ needed is, 12.7 grams.

Explanation :

First we have to calculate the moles of HCl.

$\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume of }HCl$

$\text{Moles of }HCl=6.01M\times 0.0252L=0.151mol$

Now we have to calculate the moles of $NaHCO_3$

The balanced neutralization reaction will be:

$HCl+NaHCO_3\rightarrow NaCl+H_2O+CO_2$

From the balanced chemical reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of $NaHCO_3$

So, 0.151 mole of HCl neutralizes by 0.151 mole of $NaHCO_3$

Now we have to calculate the mass of $NaHCO_3$

$\text{ Mass of }NaHCO_3=\text{ Moles of }NaHCO_3\times \text{ Molar mass of }NaHCO_3$

Molar mass of $NaHCO_3$ = 84 g/mole

$\text{ Mass of }NaHCO_3=(0.151moles)\times (84g/mole)=12.7g$

Therefore, the mass of $NaHCO_3$ needed is, 12.7 grams.

7 0

3 years ago