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lord [1]
2 years ago
7

C%3A%5C%3A%5C%3A%5C%3A%5C%3A%E2%98%9EQuestion%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%7D%7D%7D" id="TexFormula1" title="{\huge\fcolorbox{blue}{black}{\pink{\:\:\:\:\:\:\:\:\:\:\:☞Question\:\:\:\:\:\:\:\:}}}" alt="{\huge\fcolorbox{blue}{black}{\pink{\:\:\:\:\:\:\:\:\:\:\:☞Question\:\:\:\:\:\:\:\:}}}" align="absmiddle" class="latex-formula">
What is Wave Optics?

Thanks (:​
Physics
1 answer:
kumpel [21]2 years ago
3 0

the branch of optics that studies interference, diffraction, polarization, and other phenomena for which the ray approximation of geometric optics is not valid.

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The greenhouse effect is a result of
yaroslaw [1]

The answer would be D. absorption and radiation of energy in the atmosphere

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3 years ago
Which of these is an example of acceleration?
love history [14]

Answer: A

Explanation:

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How many DNA strands could you fit into a milimeter
MrRa [10]

Answer: Hopefully 50trillion DNA strands

6 0
4 years ago
To determine athletes body fat, there are weighed first in air and then again while they are completely underwater. It is found
rodikova [14]

Answer:

1065 Kgm-3

Explanation:

We can determine the relative density of the athlete from the formula;

Relative density of athlete = weight of athlete in air/upthrust on athlete

Since weight of athlete in air= 690 N

Weight of athlete in water = 42 N

Upthrust on athlete= weight in air - weight in water

Upthrust on athlete= 690 N - 42 N = 648 N

Relative density of athlete= 690 N / 648 N

Relative density of athlete= 1.065

Therefore, average density of the athlete= relative density × density of water = 1.065 × 1000 Kgm-3 = 1065 Kgm-3

4 0
4 years ago
You’re driving your car towards an intersection. A Porsche is stopped at the red light. You’re traveling at 36 km/h (10 m/s). As
34kurt

Your position at time t, relative to the stop line:

x_1=-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t

The Porsche's position:

x_2=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2

a. You pass the Porsche immediately after the time it takes for x_1=x_2:

-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=2.3\,\rm s

at which point you both will have traveled 7.8 m from the stop line.

b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about t=4.4\,\rm s, at which point you both will have traveled 29 m.

c. At time t, the Porsche is moving at velocity

v=\left(3\dfrac{\rm m}{\mathrm s^2}\right)t

so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.

6 0
4 years ago
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