Coulomb interaction is responsible
I = pressure amplitude given = 0.2 W/m²
dB = decibel reading
decibel reading from the pressure amplitude is given as
dB = 10 log₁₀ (I/10⁻¹²)
inserting the values in the above equation
dB = 10 log₁₀ (0.2/10⁻¹²)
dB = 10 log₁₀ (2 x 10⁻¹/10⁻¹²)
dB = 10 log₁₀ (2 x 10⁻¹.10¹²)
dB = 10 log₁₀ (2 x 10¹²⁻¹)
dB = 10 log₁₀ (2 x 10¹¹)
dB = 113.01 db
hence the decibel reading comes out to be 113.01 db
Answer:
The speed of cart B is 11.21 m/s.
Explanation:
Given that,
Speed of cart A = 9.25 m/s
Speed of cart B = 7.15 m/s
Mass of cart A = 72.0 kg
Mass of cart B = 55.0 kg
Speed of card A after collision = 6.15 m/s
We need to calculate the speed of cart B
Using conservation of momentum

Put the value into the formula



Hence, The speed of cart B is 11.21 m/s.
Answer:
Tension=
(g=acceleration of gravity)
Explanation:
Given that,
A 5Kg and 10Kg are attached by a cable suspended over a pulley.
As 10Kg > 5Kg , the 10 kg mass accelerates down and the 5kg mass accelerates up, let it be a. Let the tension in the cable be T.
So, the equations of motion are

Now adding them we get,


Substituting them back in the equation we get,


Answer with Explanation:
We are given that


a.We have to find the torque on the particle about the origin.
We know that
Torque=
By using the formula

b.



Substitute the values then we get



Because 
