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zzz [600]
2 years ago
15

The slope of the graphed line is. Which formulas represent the line that is graphed? Check all that apply. Y – 1 = (x – 2) y – 2

= (x – 1) y – 4 = (x – 4) f(x) = x f(x) = x.
Mathematics
1 answer:
IceJOKER [234]2 years ago
6 0

The formula or equation which represent the graphed line with point (1,2) (4,4) and slope 2/3 are,

(y-2)=\dfrac{2}{3}(x-1)\\

(y-4)=\dfrac{2}{3}(x-4)\\

<h3>What is the equation of a graphed line?</h3>

The equation of a graphed line is a way to represent the line which lies on a point on the xy-coordinated with and informed about the steepness and the direction of the line.

The standard form of the equation of a graphed line can be given as,

y=mx+c

Here, (<em>c</em>) is the y intercept of the line and (<em>m</em>) is the slope of the line.

Here, the slope of the graphed line is 2/3. The graph for this problem is attached below.

The two point in the graph below are (1,2) and (4,4). Then the equation of the line, for this two points with slope 2/3 can be given as,

(y-2)=\dfrac{2}{3}(x-1)\\

Using the points (4,4), we get,

(y-4)=\dfrac{2}{3}(x-4)\\

Thus, the formula or equation which represent the graphed line with point (1,2) (4,4) and slope 2/3 are,

(y-2)=\dfrac{2}{3}(x-1)\\

(y-4)=\dfrac{2}{3}(x-4)\\

Learn more about the equation of a line here;

brainly.com/question/18831322

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The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
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AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

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ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

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iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

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v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

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