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3 years ago

Write the neutralization equation that would take place in the stomach with two different bases used in antacid products

1 answer:

5 0

In order for the human being stomach to digest food, it uses hydrochloric acid (HCl). This is a very effective an dstrong acid that can burn the lining of the stomach and even cause ulcer if this lining does not contain enough mucus.

Back on track, a reaction between an acid and a base usually yields a salt and water. The two bases that we will use in the reaction with HCl are Mg(OH)2 and CaCO3 (note that (OH)- and (CO3)- both define basis)
MAKE SURE TO BALANCE YOU EQUATION, WHERE THE NUMBER OF MOLECULES ENTERING SHOULD BE EQUAL TO THE NUMBER OF MOLECULES RESULTING.

Equation #1:
<span>2HCl + Mg(OH)2 --> 2H2O + MgCl2
MgCl2 is the salt
</span>Equation#2:
<span>2HCl + CaCO3 --> H2O + CO2 + CaCl2</span>
CaCl2 is the salt
Carbon dioxide is formed as a result of the additional carbon carbon, the reaction ideally outputs H2CO3 which is a very weak base the breaks into water and CO2

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2 years ago

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Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

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The given equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initially conc. 0 0 0.1576

At eqm. (x) (x) (0.1576-2x)

The expression of $K_c$ will be,

$K_c=\frac{[NO]^2}{[N_2][O_2]}$

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By solving the term, we get:

$x=0.0742,0.0839$

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

Now we have to calculate the equilibrium concentration of NO.

Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M

Therefore, the equilibrium concentration of NO is, 0.0092 M.

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3 years ago

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