The pH can be defined as the negative logarithm of the hydrogen ion concentration of the solution.
<h3>What is the pH?</h3>
What we call the pH can be defined as the negative logarithm of the hydrogen ion concentration of the solution. We are aware that we can use the relation [H+] [OH-] = 1 * 10^-14 to handle the enormity of this problem.
Now, let us go about solving the problems;
1. pH = -log(1 x 10-7) = 7
2. [H+]= 1 * 10^-14/ 1 x 10^-3
pH = -log( 1 * 10^-11)
pH = 11
3. pH = -log( 1 x 10^-2)
pH = 2
4. pH = -log( 1 x 10^-10)
pH = 10
5. [H+]= 1 * 10^-14/ 1 x 10^-8
[H+]= 1 * 10^-6
pH = 6
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Answer:
A) forms a helix and no branch points
Explanation:
amylopectin: consisting of many glucose rings linked together to form lomg molecule with numerous ramifications
Explanation:
When carbon atom tends to form single bonds then its hybridization is 
, when carbon atom tends to form double bond then its hybridization is 
and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.
For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.
So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.
Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:
Answer:
Percentage composition = 14.583%
Explanation:
In chemistry, the emprical formular of a compound is the simplest formular a compound can have. It shows the simplest ratio in which the elements are combined in the compound.
Percentage composition by mass of Nitrogen
Nitrogen = 14g/mol
In one mole of the compound;
Mass of Nitrogen = 1 mol * 14g/mol = 14g
Mass of compound = 1 mol * 96.0 g/mol = 96
Percentage composition of Nitrogen = (Mass of Nitrogen / Mass of compound) * 100
percentage composition = 14/96 * 100
Percentage composition = 0.14583 * 100
Percentage composition = 14.583%
solution:
1000 = m*2400*(78-22) + m*8.79*10^5
1000= 134400m + 879000m
1000= 1030200m
m = 1000/1013400
m= 1013.4 grams
the final answer is 0.9706 grams
