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4 years ago

How does the force of gravity between two bodies change when the distance between them doubles?

Physics

1 answer:

polet [3.4K]4 years ago

7 0

Answer:

If the distance is doubled, the force of gravity between the two bodies is one-fourth as strong as before

Explanation:

The force of gravity between two bodies depends on the mass and distance. But we will focus on distance since that's what the question asks

Therefore, the force of gravity decreases as distance between the bodies increases.

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Which piece of evidence did Alfred Wegener use to develop the theory of continental drift?

Eduardwww [97]

The right answer for the question that is being asked and shown above is that: "A.tectonic activity concentrated in certain areas." A piece of evidence did Alfred Wegener use to develop the theory of continental drift is that <span>A.tectonic activity concentrated in certain areas</span>

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3 years ago

A chart showing the type of reproduction that occurs in several organisms is shown below. Organism Type of Reproduction Bacteria

quester [9]

Answer:

Explanation:

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3 years ago

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A small asteroid with a mass of 1500 kg moves near the earth. At a particular instant the asteroid’s velocity is ⟨3.5 × 104, −1.

zalisa [80]

Answer:

$P_{f}$ =(5.7 x $10^{7$ i - 2.24 x $10^{7$ j) kgm/s

Explanation:

Due to earths gravity, force on asteroid is given by:

$F= \frac{Gm_{1}m_{2} }{r^{2} }$ r^

Plugging in the values, we have

F= [(6.67x $10^{-11}$ )(1500)(5.97 x $10^{24}$ )(8x $10^{6}$ i + 9x $10^{6$ j)] / ((8x $10^{6}$ )² + (9x $10^{6$ )² $)^{1.5}$

F= 2736 i^ + 3078 j^

In order find the final momentum of the Asteroid, apply impulse momentum theorem

$P_{f}$ = $P_{i$ + FΔt

$P_{f}$ = 1500(3.5 x $10^{4$ i - 1.8x $10^{4$ j) + (2736i + 3078j)(1.5x $10^{3$ )

$P_{f}$ =(5.7 x $10^{7$ i- 2.24 x $10^{7$ j)kgm/s

4 0

4 years ago

How can i stop a headache

Klio2033 [76]

Answer:

Try to Rest.

Have a heating pad on the area where it aches.

Relax.

Or take pain pill and wait for it to settle in.

Explanation:

7 0

4 years ago

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X- rays with a wavelgnth of 0.0700 nm diffract from a crystal. Two adjacne angels of x-ray diffraciton are 45.6 and 21.0 degrees

zhenek [66]

Answer:

0.15 nm

Explanation:

d = Distance between the atomic planes

m = Order

$\theta_{m}$ = First angle = $45.6^{\circ}$

$\theta_{m+1}$ = Adjacent angle = $21^{\circ}$

$\lambda$ = Wavelength = 0.07 nm

From Bragg's relation we know

$2d\cos\theta_{m}=m\lambda$

$2d\cos45.6^{\circ}=m0.07$

$2d\cos\theta_{m+1}=(m+1)\lambda$

$2d\cos21^{\circ}=(m+1)0.07\\\Rightarrow 2d\cos21^{\circ}=m(0.07)+0.07$

$2d\cos21^{\circ}=2d\cos45.6^{\circ}+0.07\\\Rightarrow 2d(\cos21^{\circ}-\cos45.6^{\circ})=0.07\\\Rightarrow d=\dfrac{0.07}{2(\cos21^{\circ}-\cos45.6^{\circ})}\\\Rightarrow d=0.14962\ \text{nm}$

The distance between the atomic planes is 0.15 nm.

4 0

3 years ago