Answer:
T =176 N
Explanation:
from diagram
F -(m_1+m_2_g) = (m_1+m_2_g)a
440 - (6+4)g = (6+4)a
a =\frac{440-10*9.8}{10}
a =34.2 m/s^2
frrom free body diagram of mass m2 = 4kg
T -m_2g =m_2a
T = m_2(g +a)
T = 4(9.81+34.2)
T =176 N
Answer:
Example 1, if a vernier caliper output a measurement reading of 2.13 cm, this means that: The main scale contributes the main number(s) and one decimal place to the reading
E.g. 2. 1 cm, whereby 2 is the main number and 0.1 is the one decimal place number
Explanation:
plz mark as brainliest and hope it helps you
Answer:
E = 0.437 N/C
Explanation:
Given that,
Charge, 
Electric force, 
Let the strength of the electric field is E. We know that, the electric force is given by :
F = qE
Where
E is the electric field strength

So, the strength of the electric field is equal to 0.437 N/C.
Answer:
B) I1 = 1680 kg.m^2 I2 = 1120 kg.m^2
C) V = 0.84m/s T = 29.92s
D) ω2 = 0.315 rad/s
Explanation:
The moment of inertia when they are standing on the edge:
where M is the mass of the merry-go-round.
I1 = 1680 kg.m^2
The moment of inertia when they are standing half way to the center:

I2 = 1120 kg.m^2
The tangencial velocity is given by:
V = ω1*R = 0.84m/s
Period of rotation:
T = 2π / ω1 = 29.92s
Assuming that there is no friction and their parents are not pushing anymore, we can use conservation of the angular momentum to calculate the new angular velocity:
I1*ω1 = I2*ω2 Solving for ω2:
ω2 = I1*ω1 / I2 = 0.315 rad/s
Answer:
a. 240 N due east
b. 540 N due west
Explanation:
Let east be the reference direction
(a) if the resultant force has a magnitude of 390 N and points east, and the 1st force is 150N due East, then the additional force would also due east and has a magnitude of
390 - 150 = 240 N
(b) if the resultant force has a magnitude of 390 N and points west, it would be -390N is eastern reference, and the 1st force is 150N due East, then the additional force would also due east and has a magnitude of
-390 - 150 = -540 N
This force would point west