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Fofino [41]
3 years ago
8

Give two examples of vernier calliper

Physics
1 answer:
omeli [17]3 years ago
4 0

Answer:

Example 1, if a vernier caliper output a measurement reading of 2.13 cm, this means that: The main scale contributes the main number(s) and one decimal place to the reading

E.g. 2. 1 cm, whereby 2 is the main number and 0.1 is the one decimal place number

Explanation:

plz mark as brainliest and hope it helps you

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frosja888 [35]

Answer:

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Explanation:

ya so i texted maria and she said i con c()me over so letyeyey yeah betty letty

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7 0
3 years ago
A golf ball strikes a hard, smooth floor at an angle of 28.2 ° and, as the drawing shows, rebounds at the same angle. The mass o
WITCHER [35]

Answer:

    I = 1.06886  N s

Explanation:

The expression for momentum is

          I = F t = Δp

therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor

Let's find the components of the initial velocity

          sin 28.2 = v_y / v

          cos 28.2=  vₓ / v

          v_y = v sin 282

          vₓ = v cos 28.2

          v_y = 42.8 sin 28.2 = 20.225 m / s

          vₓ = 42.8 cos 28.2 = 37.72 m / s

since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making

θ = -28.2

         v_y = -20.55 m / s

         v_x = 37.72 m / s

X axis

         Iₓ = Δpₓ = p_{fx} - p_{ox}

since the ball moves in the x-axis without changing the velocity, the change in moment must be zero

         Δpₓ = m v_{fx} - m v₀ₓ = 0

          v_{fx} = v₀ₓ

therefore

          Iₓ = 0

Y axis  

        I_y = Δp_y = p_{fy} -p_{oy}

when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards

         v_{fy} = - v_{oy}

         Δp_y = 2 m v_{oy}

         Δp_y = 2 0.0260 (20.55)

         \Delta p_{y} = 1.0686 N s

the total impulse is

          I = Iₓ i ^ + I_y j ^

          I = 1.06886  j^ N s

7 0
3 years ago
The major difference between transverse and longitudinal waves is the:
Marysya12 [62]
In transversal wave particles do not oscillate along the line of the wave propagation but oscillate up and down about their mean position as the wave travels.thus transverse wave is the one in which individual particles of the medium move about their mean position in a direction perpendicular to the direction of wave propprgation.
In longitutional waves the individual particles of the medium move in the direction parallel to the direction of the propprgation of the disturbance. The particles do not move from one place to another but the simply oscillate back and forth about their position of the rest.
HOPE IT HELPS.
3 0
3 years ago
What is three example of technology
alex41 [277]
Computers, cell phones, and television
6 0
3 years ago
An electron is accelerated through 2.40×10³V from rest and then enters a uniform 1.70-T magnetic field. What are(b) the minimum
Korolek [52]

The maximum value of Force is 7.88x10^{-12}

The minimum value of magnetic force is 0

Potential V=2.40x10^{3}.

Magnetic field = B = 1.70 T.

we need to find

a) The maximum value of Force

Since the particle is moving from rest, the potential energy change is 2.40x10^{3}?

Potential Energy= vq= 2,40x10^{3}x (-1.6 x 10x10^{-19}%).

= -8.84x10^{-16}

Now this will be equal to 1/2 mv²

=  1/2 mv²= 8.84x 10^{-16}.

v=2.903x10^{7}m/s :

Wow Fmax = qvb

=1.6x10^{-19}x2.903x10^{7}x1.70 .

=7.88x10^{-12}

b) The minimum value of magnetic force

The minimum Value of magnetic force will be

when sinθ=0

The minimum value is 0

To know more about magnetic field refer to brainly.com/question/13091447

#SPJ4

5 0
2 years ago
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