Answer:
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Explanation:
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Answer:
I = 1.06886 N s
Explanation:
The expression for momentum is
I = F t = Δp
therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor
Let's find the components of the initial velocity
sin 28.2 = v_y / v
cos 28.2= vₓ / v
v_y = v sin 282
vₓ = v cos 28.2
v_y = 42.8 sin 28.2 = 20.225 m / s
vₓ = 42.8 cos 28.2 = 37.72 m / s
since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making
θ = -28.2
v_y = -20.55 m / s
v_x = 37.72 m / s
X axis
Iₓ = Δpₓ = 
since the ball moves in the x-axis without changing the velocity, the change in moment must be zero
Δpₓ = m
- m v₀ₓ = 0
v_{fx} = v₀ₓ
therefore
Iₓ = 0
Y axis
I_y = Δp_y = p_{fy} -p_{oy}
when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards
v_{fy} = - v_{oy}
Δp_y = 2 m v_{oy}
Δp_y = 2 0.0260 (20.55)
= 1.0686 N s
the total impulse is
I = Iₓ i ^ + I_y j ^
I = 1.06886 j^ N s
In transversal wave particles do not oscillate along the line of the wave propagation but oscillate up and down about their mean position as the wave travels.thus transverse wave is the one in which individual particles of the medium move about their mean position in a direction perpendicular to the direction of wave propprgation.
In longitutional waves the individual particles of the medium move in the direction parallel to the direction of the propprgation of the disturbance. The particles do not move from one place to another but the simply oscillate back and forth about their position of the rest.
HOPE IT HELPS.
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The maximum value of Force is 7.88x
The minimum value of magnetic force is 0
Potential V=2.40x
.
Magnetic field = B = 1.70 T.
we need to find
a) The maximum value of Force
Since the particle is moving from rest, the potential energy change is 2.40x
?
Potential Energy= vq= 2,40x
x (-1.6 x 10x
%).
= -8.84x
Now this will be equal to 1/2 mv²
= 1/2 mv²= 8.84x
.
v=2.903x
m/s :
Wow Fmax = qvb
=1.6x
x2.903x
x1.70 .
=7.88x
b) The minimum value of magnetic force
The minimum Value of magnetic force will be
when sinθ=0
The minimum value is 0
To know more about magnetic field refer to brainly.com/question/13091447
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