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Doss [256]
2 years ago
11

What must the charge (sign and magnitude) of a particle of mass 1.40 gg be for it to remain stationary when placed in a downward

-directed electric field of magnitude 640 N/CN/C
Physics
1 answer:
NISA [10]2 years ago
4 0

Answer:

the charge of the particle is -2.144 x 10⁻⁵ C.

Explanation:

The force acting on the particle is calculated as;

F = EQ = mg

Q = \frac{mg}{E}

where;

Q is magnitude of the charge of the particle

Q = \frac{(1.4\times 10^{-3})(9.8)}{640} \\\\Q = 2.144 \ \times \ 10^{-5} \ C

since the magnetic field is acting downward, the force must be acting upward in opposite direction.

Thus, the charge of the particle will be -2.144 x 10⁻⁵ C.

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Explanation:

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You are trying to climb a castle wall so, from the ground, you throw a hook with a rope attached to it at 24.1 m/s at an angle o
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Answer:

The value is  h  =  13.2 \  m

Explanation:

From the question we are told that

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Generally from kinematic equation we have that

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Here h is the height of the wall so

      [16.3 sin (65)]^2 =  [24.1 sin (65)] ^2+   2 (-9.8)* h

=>    h  =  13.2 \  m

4 0
3 years ago
A hop is a springing from one foot but landing on the other foot? Question 4 options: True False
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Answer:

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Answer:

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