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Doss [256]
2 years ago
11

What must the charge (sign and magnitude) of a particle of mass 1.40 gg be for it to remain stationary when placed in a downward

-directed electric field of magnitude 640 N/CN/C
Physics
1 answer:
NISA [10]2 years ago
4 0

Answer:

the charge of the particle is -2.144 x 10⁻⁵ C.

Explanation:

The force acting on the particle is calculated as;

F = EQ = mg

Q = \frac{mg}{E}

where;

Q is magnitude of the charge of the particle

Q = \frac{(1.4\times 10^{-3})(9.8)}{640} \\\\Q = 2.144 \ \times \ 10^{-5} \ C

since the magnetic field is acting downward, the force must be acting upward in opposite direction.

Thus, the charge of the particle will be -2.144 x 10⁻⁵ C.

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