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Bezzdna [24]
3 years ago
12

A car slows from 22m/s to 3.0m/a at a constant rate of 2.1m/s. How many seconds are required before the car is traveling at 3.0m

/s?
Physics
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

t = 9.05 s

Explanation:

Given,

The initial velocity of the car, u = 22 m/s

The final velocity of the car, v = 3.0 m/s

The rate of change of speed of the car is 2.1 m/s,

                                      ∴ the acceleration, a = -2.1 m/s²

The acceleration and velocity is given by the relation

                                           a = (v - u)/t     m/s²

Therefore,

                                           t = (v-u)/a  s

Substituting the values in the above equation

                                          t = (3.0 - 22)/(-2.1)

                                            = 9.05 s

Hence, the time required before the car is traveling at 3.0m/s is t = 9.05 s

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An underground gasoline tank can hold 1.07 103 gallons of gasoline at 52.0°F. If the tank is being filled on a day when the outd
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1069.38 gallons

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Let V₀ = 1.07 × 10³ be the initial volume of the gasoline at temperature θ₁ = 52 °F. Let V₁ be the volume at θ₂ = 97 °F.

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