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Bezzdna [24]
3 years ago
12

A car slows from 22m/s to 3.0m/a at a constant rate of 2.1m/s. How many seconds are required before the car is traveling at 3.0m

/s?
Physics
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

t = 9.05 s

Explanation:

Given,

The initial velocity of the car, u = 22 m/s

The final velocity of the car, v = 3.0 m/s

The rate of change of speed of the car is 2.1 m/s,

                                      ∴ the acceleration, a = -2.1 m/s²

The acceleration and velocity is given by the relation

                                           a = (v - u)/t     m/s²

Therefore,

                                           t = (v-u)/a  s

Substituting the values in the above equation

                                          t = (3.0 - 22)/(-2.1)

                                            = 9.05 s

Hence, the time required before the car is traveling at 3.0m/s is t = 9.05 s

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An automobile traveling 95 km/h overtakes a 1.30-km-long train traveling in the same direction on a track parallel to the road.
SOVA2 [1]

Answer:

Same direction: t=234s; d=6.175Km

Opposite direction: t=27.53s; d=0.73Km

Explanation:

If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be v_{AT}=v_A-v_T (<em>the train must see the car advancing at a lower speed</em>), where v_A is the speed of the automobile and v_T the speed of the train.

So we have v_{AT}=(95km/h)-(75Km/h)=20Km/h.

So the train (<em>anyone in fact</em>) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

t = \frac{L}{v_{AT}} = \frac{1.3Km}{20Km/h} = 0.065h=234s

And in that time the car would have traveled (<em>relative to the ground</em>):

d=v_At=(95Km/h)(0.065h)=6.175Km

If they are traveling in opposite directions, <u>we have to do all the same</u> but using v_{AT}=v_A+v_T (<em>the train must see the car advancing at a faster speed</em>), so repeating the process:

v_{AT}=(95km/h)+(75Km/h)=170Km/h

t = \frac{L}{v_{AT}} = \frac{1.3Km}{170Km/h} = 0.00765h=27.53s

d=v_At=(95Km/h)(0.00765h)=0.73Km

5 0
3 years ago
How are the components of a heterogeneous mixture distributed?
Lena [83]

Answer:

heterogeneous mixture has components that are not evenly distributed. This means that you can easily distinguish between the different components.

3 0
3 years ago
A railroad freight car, mass 15,000 kg, is allowed to coast along a level track at a speed of 2.0 m/s. It collides and couples w
gayaneshka [121]

Answer:

The speed of the two cars after coupling is 0.46 m/s.

Explanation:

It is given that,

Mass of car 1, m₁ = 15,000 kg

Mass of car 2, m₂ = 50,000 kg

Speed of car 1, u₁ = 2 m/s

Initial speed of car 2, u₂ = 0

Let V is the speed of the two cars after coupling. It is the case of inelastic collision. Applying the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{15000\ kg\times 2\ m/s+0}{(15000\ kg+50000\ kg)}  

V = 0.46 m/s

So, the speed of the two cars after coupling is 0.46 m/s. Hence, this is the required solution.          

3 0
3 years ago
Suppose a tank filled with water has a liquid column with a height of 10 meters. If the area is 2 square meters (2 m²), what's t
Vesna [10]

Answer:

196000 N

Explanation:

The following data were obtained from the question:

Height (h) = 10 m

Area (A) = 2 m²

Force (F) =.?

Next, we shall determine the pressure in the tank.

This can be obtained as follow:

P = dgh

Where

P is the pressure.

d is the density of the liquid.

g is acceleration due to gravity

h is the height.

Height (h) = 10 m

Density (d) of water = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Pressure (P) =...?

P = dgh

P = 1000 × 9.8 × 10

P = 98000 N/m²

Therefore, the pressure acting on the tank is 98000 N/m²

Finally, we shall determine the force of gravity acting on the column of water as follow:

Area (A) = 2 m²

Pressure (P) = 98000 N/m²

Force (F) =.?

Pressure (P) = Force (F) /Area (A)

P = F /A

98000 = F/ 2

Cross multiply

F = 98000 × 2

F = 196000 N

Therefore, the force of gravity acting on the column of water is 196000 N

4 0
3 years ago
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Simora [160]
A, hope this helped! I didn’t really get it but I think it’s correct?
3 0
3 years ago
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