A car slows from 22m/s to 3.0m/a at a constant rate of 2.1m/s. How many seconds are required before the car is traveling at 3.0m
1 answer:
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Answer:
Stunt Car A experiences a large force over a short period of time. Stunt Car B experiences a small force over a long period of time. Because of the force experienced by Stunt Car A, it will sustain more damage than Stunt Car B.
Explanation:
Both cars have the same mass and velocity, therefore they have the same momentum. During the collision, the total momentum of the car A and brick wall is conserved as well as the total momentum of the car B and the pile of leaves.
However, if we are to investigate the damage on each car, we should look at the cars not the whole system. So, the momentum difference between the cars gives us the impulse that the car felt.
Since the Car A will crash the wall quicker than the other car crashes through the pile of leaves,
which gives us
Answer:
Total pressure =1.01*10^5 Pa
Explanation:
given data:
atmospheric pressure = 1.013 *10^5 Pa\
height of water column = 60 cm
Total pressure will be sum of atmospheric pressure and pressure due to water column
P = Atmospheric pressure + pressure due to water column
pressure due to water =
\rho of water = 1420 kg/m^{3}
height of water column = 60 cm =0.60 m
Total pressure = 109649.6 Pa = 1.10*10^5 Pa
Total pressure =1.01*10^5 Pa