<u>Answer:</u>
<em>Thunderbird is 995.157 meters behind the Mercedes</em>
<u>Explanation:</u>
It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird decided to take a pit stop and slows down for 250 m. She spent 5 seconds in the pit stop.
Here final velocity 
initial velocity
distance
Distance covered in the slowing down phase = 







The car is in the pit stop for 5s 
After restart it accelerates for 350 m to reach the earlier velocity 71 m/s





total time= 
Distance covered by the Mercedes Benz during this time is given by 
Distance covered by the Thunderbird during this time=
Difference between distance covered by the Mercedes and Thunderbird
= 
Thus the Mercedes is 995.157 m ahead of the Thunderbird.
Answer
given,
v = 128 ft/s
angle made with horizontal = 30°
now,
horizontal component of velocity
vx = v cos θ = 128 x cos 30° = 110.85 ft/s
vertical component of velocity
vy = v sin θ = 128 x sin 30° = 64 m/s
time taken to strike the ground
using equation of motion
v = u + at
0 =-64 -32 x t
t = 2 s
total time of flight is equal to
T = 2 t = 2 x 2 = 4 s
b) maximum height
using equation of motion
v² = u² + 2 a h
0 = 64² - 2 x 32 x h
64 h = 64²
h = 64 ft
c) range
R = v_x × time of flight
R = 110.85 × 4
R = 443.4 ft
Over short to medium distance, the shape of a projectile"s path is a PARABOLA.
<span>d) While taking a shower, I saw a little mouse scurry across the bathroom floor.
This sentence is ordered properly. </span>