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Margaret [11]
2 years ago
12

Just before hitting the ball to the ground the ball had a kinetic energy of 12.5 J. Calculate the velocity of which the ball hit

s the ground
Physics
1 answer:
lesantik [10]2 years ago
3 0

Answer:

v = √(25/m)

Explanation:

KE = ½mv²

v = √(2KE/m)

We know the kinetic energy, but not the mass

v = √(25/m)

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A paintball’s mass is 0.0032kg. A typical paintball strikes a target moving at 85.3 m/s.
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Answer:

A)  If the paintball stops completely the magnitude of the change in the paintball’s momentum is  p=0.273kg*m/s

B) If the paintball bounces off its target and afterward moves in the opposite direction with the same speed, the change in the paintball’s momentum is  p=0.546kg*m/s

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Explanation:

Hi

A) We use the formula of momentum p=mv, so we have p=0.0032kg*85.3m/s=0.273kg*m/s

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C) The average strength of the force an object exerts during impact is determined by the amount the object’s momentum changes. therefore

F=\frac{\Delta p}{\Delta t}, as we don't have any data about the impact time but we know momentum is twice, time does no matter and strength is twice too.

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