Answer:
The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.
Explanation:
Hope this helps :)
Answer:
27 blocks
Explanation:
First, the expression to use here is the following:
P = F/A
Where:
P: pressure
F: Force exerted
A: Area of the block.
Now , we need to know the number of blocks needed to exert a pressure that equals at least 2 atm. To know this, we should rewrite the equation. We know that certain number of blocks, with the same weight and dimensions are putting one after one over the first block, so we can say that:
P = W/A
P = n * W1 / A
n would be the number of blocks, and W1 the weight of the block.We have all the data, and we need to calculate the area of the block which is:
A = 0.2 * 0.1 = 0.02 m²
Solving now for n:
n = P * A / W1
The pressure has to be expressed in N/m²
P = 2 atm * 1.01x10^5 N/m² atm = 2.02x10^5 N/m²
Finally, replacing all data we have:
n = 2.02x10^5 * 0.02 / 150
n = 26.93
We can round this result to 27. So the minimum number of blocks is 27.
Answer:
The size of the image is 1.04 m.
Explanation:
Given that,
Height of object = 2.40 m
Distance of object = 2.60 m
Radius of curvature =4.00 m
Focal length 
We need to calculate the image distance
Using mirror formula
We need to calculate the height of the image
Using formula of magnification
Put the value into the formula
Hence, The size of the image is 1.04 m
It's a multiple of 5 because you can't multiply anything by 2 and get 25
I will be making the assumption that you aren't actually really throwing the object over a bridge but rather dropping it as no initial velocity is actually given, which is required to do this problem. This will mean that initial velocity will be zero in this case.
First off, let's state all of the information we are given (the five kinematic quantities)
v₁ = 0 m/s
v₂ = cannot be determined
Δd = ?
Δt = 8 seconds
a (g) = 10 m/s² [down]
Now analyzing what we have, we can determine that we have 3 given quantities, 1 we must solve for, and 1 that cannot be found given our current information.
The five kinematic equations are useful because they all contain four kinematic quantities, and with different combinations too. In this case, we have three (v₁, Δt, a) and have to solve for Δd. The kinematic equation that fits with this would be:
Δd = v₁Δt + 0.5(a)(t)²
We can plug in our given values now.
Δd = 0 m/s(8 s) + 0.5(10 m/s²)(8 s)²
Δd = 0.5(10 m/s²)(8 s)²
Δd = <u>3</u>20 m
Therefore, the total displacement of the object would have to be 300m. (Due to significant digit rules)
