It would be 2300000 grams.
Answer:
b- a bicycle sitting on the ground
Explanation:
'Static' means it's not moving.
So, only the answer listed as "a bicycle sitting on the ground" corresponds to that condition.
All others possible answers describe something that is moving (an apple falling, a motorcycle accelerating, a car moving at a constant speed). Even if they are going at a constant speed, they are moving, so not static.
Answer:
Part b)
Part c)
Explanation:
The two components of the velocity of the ball is given as
Part a)
now we know that the displacement in y direction is given as
so we have
Part b)
Distance of the ball in x direction of the motion is given as
Part c)
In x direction the velocity will remain the same always
while in Y direction we can use kinematics
Using the constant acceleration formula v^2 = u^2 + 2as, we can figure out that it would take a distance of 193.21m to reach 27.8m/s
Answer:
The runners are 0.159 mi to the west of the flagpole.
Explanation:
Let´s place the origin of the frame of reference at the point where the flagpole is located.
The initial position of runner A is 3.91 mi and his velocity is -6.04 mi/h
The initial position of runner B is -2.95 mi and his velocity is 5.00 mi/h
When both runners meet, their position is the same. The equation of the position of each runner is:
x = x0 + v · t
Where
x = position at time t
x0 = initial position
v = velocity
t = time
Then, at the meeting point:
x runner A = x runner B
3.91 mi - 6.04 mi/h · t = -2.95 mi + 5.00m/h · t
Solving for t:
3.91 mi + 2.95 mi = 5.00m/h · t + 6.04 mi/h · t
6.86 mi = 11.04 mi/h · t
t = 0.621 h
Now, we use this time to find the meeting point. We can use the equation of any runner. Let´s use the position of runner A:
x = 3.91 mi - 6.04 mi/h · 0.621 h = 0.159 mi
Since the position is positive, the runners met 0.159 mi to the west of the flagpole.