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labwork [276]
3 years ago
5

If a Nissan Titan has a mass of 2,300 kilograms how many grams is that

Physics
1 answer:
padilas [110]3 years ago
6 0

It would be 2300000 grams.

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A 0.49 m copper rod with a mass of 0.15 kg carries a current of 13 A in the positive y direction. Let upward be the positive dir
Helen [10]

Answer:

Magnetic field, B = 0.23 T          

Explanation:

Given that,

Length of the copper rod, L = 0.49 m

Mass of the copper rod, m = 0.15 kg

Current in rod, I = 13 A (in +ve y direction)

When the rod is placed in magnetic field, the magnetic force is balanced by its weight such that :

BIL=mg\\\\B=\dfrac{mg}{IL}\\\\B=\dfrac{0.15\times 9.8}{13\times 0.49}\\\\B=0.23\ T

So, the magnitude of the minimum magnetic field needed to levitate the rod is 0.23 T.

6 0
3 years ago
Hii so I am out of town unable to do this for my class can you guys use things in your own home? I will BRAINLIST!!1
ExtremeBDS [4]
1.)t.v
2.) tablet
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7 0
2 years ago
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Use the Divergence Theorem to calculate the surface integral
MrRa [10]
Divergense theorem says flux across the closed surface = ∫∫∫ div F dV 

<span>div F = 3y^2+ 3 z^2 </span>
<span>convert to cylindrical </span>
<span>y = r cos t </span>
<span>z = r sin t </span>
<span>x = x </span>
<span>dx dy dz = r dx dr dt </span>

<span>∫ [0, 2pi]∫[0,3]∫ [-1,3] 3r^3 dx dr dt </span>

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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
3 0
3 years ago
Is oil a compound or element​
morpeh [17]

Oil is a compound.

The species which contain more than one element is called compound. Oil is a mixture of many elements like liquid hydrocarbons, oxygen, nitrogen, sulphur, hydrogen gas etc. This elements form a large variety of structure.

5 0
2 years ago
Read 2 more answers
What angle would the axis of a polarizing filter need to make with the direction of polarized light of intensity 1.00 kW/m2 to r
iragen [17]

Answer:

The angle is 84.26⁰

Explanation:

The angle the axis of a polarizing filter need to make with the direction of polarized light is given by;

I = I₀Cos²θ

where;

I is the intensity of the polarized light transmitted from the polarizer

I₀ is the intensity of the polarized light incident on the polarizer

Given;

I₀ = 1.00 kW/m² = 1000 W/m²

I = 10 W/m²

Cos^2 \theta = \frac{I}{I_o}\\\\Cos \theta = \sqrt{\frac{I}{I_o}}\\\\\theta = Cos^{-1}( \sqrt{\frac{I}{I_o}})\\\\\theta = Cos^{-1}( \sqrt{\frac{10}{1000}})\\\\\theta = 84.26^0

Therefore, the angle is 84.26⁰

3 0
3 years ago
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