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Snowcat [4.5K]
2 years ago
14

When three 30-ohm resistors are connected in parallel across a 9-volt source, the total current is

Physics
1 answer:
PSYCHO15rus [73]2 years ago
4 0
—-Answer in photo :)

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Five liters of air at 50 c is warmed to 100c what is the new volume if the pressure remain constant
KonstantinChe [14]
To solve the problem, we can use Charle's law, which states that for an ideal gas at constant pressure the ratio between absolute temperature T and volume V remains constant:
\frac{T}{V}=k
For a gas transformation, this law can be rewritten as
\frac{T_1}{V_1}= \frac{T_2}{V_2} (1)
where 1 and 2 label the initial and final conditions of the gas.

Before applying the law, we must convert the temperatures in Kelvin:
T_1 = 50^{\circ}C + 273 = 323 K
T_2 = 100^{\circ}C+273=373 K
The initial volume of the gas is V_1 = 5 L, so if we re-arrange (1) we find the new volume of the gas:
V_2 = V_1  \frac{T_2}{T_1}=(5 L) \frac{373 K}{323 K}=5.77 L
8 0
3 years ago
A loudspeaker, mounted on a tall pole, is engineered to emit 75% of its sound energy into the forward hemisphere, 25% toward the
Naily [24]

Answer:

"0.049 W" is the correct answer.

Explanation:

According to the given question,

r = \sqrt{(3.5)^2+(2.5)^2}

  =\sqrt{8.5}

SL=85

As we know,

⇒  SL=10 \ log(\frac{I}{I_o} )

     85=10 \ log(\frac{I}{10^{-12}} )

      I=3.162\times 1^{-4} \ W/m^2

Now,

⇒  P_{front} = I(2\pi r^2)

               =(3.162\times 10^{-4})(2\pi\times 18.5)

               =0.0368 \ W

               =0.75 \ P

or,

                =0.049 \ W

7 0
3 years ago
How does mass affect the change in velocity of an object? Immersive Reader
Bas_tet [7]

Answer:

I would say the 3rd one

Explanation:

5 0
3 years ago
What are the two opposite sides of a magnet called?
dexar [7]
The 2 sides of magnet are called the north and south pole

8 0
4 years ago
Read 2 more answers
A runner has a temperature of 40°c and is giving off heat at the rate of 50cal/s (a) What is the rate of heat loss in watts? (b)
Andrew [12]

Answer:

(a)  209 Watt

(b) 4482.8 seconds

Explanation:

(a) P = 50×4.18

Where P = rate of heat loss in watt

    P = 209 Watt

Applying,

Q = cm(t₁-t₂)................ Equation 1

Where Q = amount of heat given off, c = specific heat capacity capacity of human, m = mass of the person, t₁ and t₂ = initial and final temperature.

From the question,

Given: m = 90 kg, t₁ = 40°C, t₂ = 37°C

Constant: c = 3470 J/kg.K

Substtut these values into equation 1

Q = 90×3470(40-37)

Q = 936900 J

But,

P = Q/t.............. Equation 2

Where t = time

t = Q/P............ Equation 3

Given: P = 209 Watt, Q = 936900

Substitute into equation 3

t = 936900/209

t = 4482.8 seconds

5 0
3 years ago
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