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LiRa [457]
3 years ago
11

1. What are small-scale techniques in chemistry? ​

Chemistry
1 answer:
stira [4]3 years ago
4 0

Answer:Small-scale technique means a small quantity of chemicals that contribute to the safety of the experiments. Instead of using big beaker of chemical, micro scale technique utilize small quantities of chemical and scaled-down science equipment.

Explanation:

You might be interested in
How many molecules are there in 0.565 moles of C6H14?
Sauron [17]

Answer:

3.4 × 10^23 molecules

Explanation:

To find the number of molecules present in C6H14, we multiply the number of moles in the compound by Avagadro's number (6.02 × 10^23 atoms).

number of molecules = number of moles (mol) × 6.02 × 10^23?

Number of molecules = 0.565 × 6.02 × 10^23

3.4 × 10^23 molecules

6 0
2 years ago
Use a reference source to identify five facts about a neutron star or a black hole. Don’t forget to cite your sources.
sleet_krkn [62]

Answer:

Black holes are astronomical objects that have such strong gravity, not even light can escape. Neutron stars are dead stars that are incredibly dense. ... Both objects are cosmological monsters, but black holes are considerably more massive than neutron stars.

Explanation:

3 0
3 years ago
For the reaction 2Fe + 3Cl2 → 2FeCl3 which of the following options gives the correct reactant:reactant ratio? Fe:Cl2 = 1:1 Fe:C
BigorU [14]

Answer: Fe:Cl2 = 2:3

Explanation:

8 0
3 years ago
4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

8 0
3 years ago
Which statement best describes the effects chemicals may have on the
frutty [35]
The answer is B. So yeah
7 0
3 years ago
Read 2 more answers
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