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Elodia [21]
3 years ago
11

Grignard reactions are highly exothermic and are performed in ether solvent. There is a real risk of fire during this reaction.

In the case that a fire should occur in your distillation apparatus, what is the best course of action?
Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

Ideally, extinguish the flames with a glass watch or beaker.

Explanation:

When you cover the distillation equipment with a watch glass or beaker, you reduce the oxygen content and it is completely eliminated thanks to the fire itself that consumes it. Once there is no more oxygen the fire is extinguished and it should take no more than 2 or 3 seconds to occur this situation

It is the easiest and most careful way to extinguish the fire during the Grignard reaction

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All of the following reactions can be described as displacement reactions except:____________.
Lady_Fox [76]

Answer:

b

Explanation:

The reaction that is not a displacement reaction from all the options is C_6H_6_{(l)} + Cl_{2(g)} --> C_6H_5Cl_{(l)} + HCl_{(g)}

In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.

<em>Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.</em>

Correct option = b.

8 0
3 years ago
Hurry!!
pishuonlain [190]

Answer:

condensation is the answer

6 0
2 years ago
Read 2 more answers
When the pressure that a gas exerts on a sealed container changes from 1100 bar to 75.5 bar, the temperature changes from k to 2
Serjik [45]
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
\frac{P1}{T1} =  \frac{P2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{1100 bar}{T}  =  \frac{75.5 bar}{298 K}
T = 4342 K
initial temperature was 4342 K
7 0
3 years ago
Determine the concentration of a solution prepared by diluting 20.0 ml of a 0.200 m rbcl to 250.0 ml. determine the concentratio
pogonyaev
When dealing with making diluted solutions from concentrated solutions, we can use the following formula 
c1v1 = c2v2 
where c1 and v1 are the concentration and volume of the concentrated solution respectively.
c2 and v2 are the concentration and volume of the diluted solution respectively 
substituting these values in the above formula,
20 mL x 0.200 M = C x 250.0 mL 
C = 0.0160 M 
5 0
2 years ago
Calculate the concentration in mol/L, M, of an aqueous sugar solution with a concentration of 23.5% (w/w) and density of 1.005 g
Temka [501]

Answer:

The concentration in mol/L is 0.683M

Explanation:

23.5% (w/w)

This data means that in 100 g of solution, we have 23.5 grams of solute.

From this point, we can calculate the moles of sugar.

Moles = Mass / Molar mass

Moles = 23.5 g /342.30 g/m

Moles = 0.068 moles

Density data make us know, the volume of our solution.

solution δ = solution mass / solution volume

δ = 1.005 g/mL = 100 g /  solution volume

solution volume = 100g / 1.005 g/ml

solution volume = 99.5 mL

In conclusion, 0.068 moles are in 99.5 mL

Molarity (M) is mol/L

Let's convert 99.5 mL in L

99.5 mL / 1000 = 0.0995 L

0.068 m / 0.0995L = 0.683

<em>If we convert moles in mmoles, we can also get Molarity (M)</em>

<em>mmoles / mL = M</em>

<em>0.068 moles . 1000 = 68 mmoles</em>

<em>68 mmmoles / 99.5mL = 0.683</em>

8 0
3 years ago
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