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Fittoniya [83]
2 years ago
10

Please help i’ll give you so many points

Physics
1 answer:
Mars2501 [29]2 years ago
7 0

Answer:

See below

Explanation:

Steady speed = constant slope = A

Increasing speed = increasing slope = C

B is decreasing speed

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The spring of a toy car is wound by pushing the car
Zepler [3.9K]

The elastic potential energy stored in the car's spring during the process is 3.75 J

<h3>Determination of the spring constant</h3>

From the question given above, the following data were obtained:

  • Force (F) = 15 N
  • Extention (e) = 0.5 m
  • Spring constant (K) =?

K = F/e

K = 15 / 0.5

K = 30 N/m

<h3>Determination of the potential energy</h3>
  • Spring constant (K) = 30 N/m
  • Extention (e) = 0.5 m
  • Potential energy (PE) =?

PE = ½Ke²

PE = ½ × 30 × 0.5²

PE = 15 × 0.25

PE = 3.75 J

Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J

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Which graph below represents how the velocity of the sphere changes over time when falling with constant acceleration?
Amiraneli [1.4K]

Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.

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To solve this exercise it is necessary to apply the concepts related to Centripetal and Perimeter acceleration of a circle.

The perimeter of a circle is defined by

P = 2\pi r

Where,

r= radius

While centripetal acceleration is defined by

a=\frac{v^2}{r}

Where,

v= velocity

r= radius

PART A)

The distance of a body can be defined based on the speed and the time traveled, that is

x = v*t

For our values the distance is equal to

x = 15*115=1725m

The plane when going to make the turn from east to south makes a quarter of the circumference that is

\frac{P}{4} = \frac{2\pi r}{4}

The same route you take is the distance traveled, that is

x = \frac{P}{4}

x = \frac{2\pi r}{4}

1725 = \frac{2\pi r}{4}

r = 1098.17m

PART B)

With the radius is possible calculate he centripetal acceleration,

a = \frac{v^2}{r}

a = \frac{115^2}{1098.17}

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Therefore the radius of the curva that the plane follows in making the turn is 1098.17m with a centripetal acceleration of 12.04m/s^2

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