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oee [108]
3 years ago
5

Which career is most concerned with the study of radioactive isotopes?

Physics
1 answer:
leonid [27]3 years ago
3 0
<span>The career that is most concerned with the study of radioactive isotopes is chemistry. You need to have passed AP chemistry to actually deal with the isotopes. In a quick reference, isotopes are when the atom has difference amount of neutrons, making the atomic mass differ.</span>
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Which diagram shows diffraction as light passes through an opening?
Bingel [31]
I don’t see the diagram
3 0
3 years ago
Read 2 more answers
Why are computer simulations useful in studying phenomena in the universe?
kenny6666 [7]

Computer simulation is useful because it helps in the prediction of what will likely happen in the future using data from past events.

<h3>What is computer simulation?</h3>
  • This is the use of computer models to represents a hypothetical scenarios that are likely to be obtained in the real world.

Computer simulations are useful in studying phenomena in the universe because they help us to achieve the followings;

  • It helps in the prediction of what will likely happen in the future using data from past events.
  • It saves cost and time of carrying out actual experiments.
  • It can help prevent a disaster that may occur in the future.

Learn more about computer simulations here: brainly.com/question/22214039

5 0
2 years ago
Derive the equation of motion of the block of mass m1 in terms of its displacement x. The friction between the block and the sur
Alenkasestr [34]

Answer:

the equivalent mass : m_e = m_1+m_2+\frac{I}{R^2}

the equation of the motion of the block of mass m_1 in terms of its displacement is = (m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)

Explanation:

Let use m₁ to represent the mass of the block and m₂ to represent the mass of the cylinder

The radius of the cylinder  be = R

The distance between the center of the pulley to center of the block to be = x

Also, the angles of inclinations of the cylinder and the block with respect to the ground to be \phi and \beta respectively.

The velocity of the block to be = v

The equivalent mass of the system = m_e

In the terms of the equivalent mass, the kinetic energy of the system can be written as:

K.E = \frac{1}{2} m_ev^2       --------------- equation (1)

The angular velocity of the cylinder = \omega  :  &

The inertia of the cylinder about its center to be = I

The angular velocity of the cylinder can be written as:

v = \omega R

\omega =\frac{v}{R}

The kinetic energy of the system in terms of individual mass can be written as:

K.E = \frac{1}{2}m_1v^2+\frac{1}{2} m_2v^2+\frac{1}{2}I\omega^2

By replacing \omega with \frac{v}{R} ; we have:

K.E = \frac{1}{2}m_1v^2+\frac{1}{2} m_2v^2+\frac{1}{2}I(\frac{v}{R})^2

K.E = \frac{1}{2}(m_1+ m_2+ \frac{I}{R} )v^2   ------------------ equation (2)

Equating both equation (1) and (2); we have:

m_e = m_1+m_2+\frac{I}{R^2}

Therefore, the equivalent mass : m_e = m_1+m_2+\frac{I}{R^2}    which is read as;

The equivalent mass is equal to the mass of the block plus the mass of the cylinder plus the inertia by  the square of the radius.

The expression for the force acting on equivalent mass due to the block is as follows:

f_{block }=m_1gsin \beta

Also; The expression for the force acting on equivalent mass due to the cylinder is as follows:

f_{cylinder} = m_2gsin \phi

Equating the above both equations; we have the equation of motion of the  equivalent system to be

m_e \bar x = f_{cylinder}-f_{block}

which can be written as follows from the previous derivations

(m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)

Finally; the equation of the motion of the block of mass m_1 in terms of its displacement is = (m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)

8 0
3 years ago
A girl travels 20 miles on her bike, the trip takes two hours. express her speed in miles/hr
xxTIMURxx [149]

Answer:

10 mph

Explanation:

6 0
2 years ago
A bus accelerates from 5.75 m/s at a rate of 1.25 m/s/s for 3.50
marysya [2.9K]

Answer:

10.125 meters?

Explanation:

Im taking 5.75m/s + 1.25 m/s/s (3.5) = my answer.

In those 3.5 seconds it travels 4.375.

I added that to 5.75 to get 10.125m

3 0
3 years ago
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