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IgorLugansk [536]
3 years ago
12

What was the initial velocity of a robot that took 5 m to get to final velocity of 19 m/s at a rate of 3 m/s/s?

Physics
1 answer:
Aleks [24]3 years ago
5 0

Answer:

4m/s

v=u+at

19=u+3*5

u=4m/s

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A Formula One race car with mass 770.0 kg is speeding through a course in Monaco and enters a circular turn at 235.0 km/h in the
Marat540 [252]

Answer:

Explanation:

Given

mass of first car m_1=770 kg

speed =235 km/h\approx 65.27 m/s

radius of first turn=125 m

And Angular momentum is given by =mvr

Angular momentum of first car

L_1=770\times 65.27\times 125=6282,237.5 N-m/s

v_2=190\approx 52.77 m/s

r_2=100m

similarly L_2=770\times 52.77\times 100=4063290 N-m/s

\frac{L_1}{L_2}=\frac{r_1v_1}{r_2v_2}=\frac{125\times 65.27}{100\times 52.77}=1.546

Thus angular momentum of first car is 1.54 times of second one

4 0
3 years ago
Which of the following represents thermal energy transfer through radiation
Bogdan [553]

C. since the the heat from the heater is going to the child in <u>waves</u>, it’s<u> radiating </u>

3 0
3 years ago
A girl at an airport rolls a ball north on a moving walking that moves east. If the ball’s speed with respect to the walkway is
sweet-ann [11.9K]

We have to add two vectors.

Vector #1: 0.15 m/s north

Vector #2: 1.50 m/s east

Their sum:

Magnitude: √(0.15² + 1.50²)

Magnitude = √(0.0225+2.25)

Magnitude = √2.2725

Magnitude = <em>1.5075 m/s</em>

Direction = arctan(0.15/1.50) north of east

Direction = <em>5.71° north of east</em>

4 0
3 years ago
ListenA bicycle and its rider have a combined mass of 80. kilograms and a speed of 6.0 meters per second. What is the magnitude
Setler [38]

Answer:

a) 1.2\times 10^2\ N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

a = Acceleration

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{0-6}{4}\\\Rightarrow a=-1.5\ m/s^2

The acceleration of the bicycle and rider is -1.5 m/s²

Force

F=ma\\\Rightarrow F=80\times -1.5\\\Rightarrow F=-120\ N=-1.2\times 10^2\ N

The magnitude of the average force needed to bring the bicycle and its rider to a stop is 1.2\times 10^2\ N

3 0
3 years ago
The dome of a Van de Graaff generator receives a charge of 0.00011 C. The radius of the dome is 5.2 m. Find the strength of the
wel

Answer:

Answer:

Explanation:

Given that

K=8.98755×10^9Nm²/C²

Q=0.00011C

Radius of the sphere = 5.2m

g=9.8m/s²

1. The electric field inside a conductor is zero

εΦ=qenc

εEA=qenc

net charge qenc is the algebraic sum of all the enclosed positive and negative charges, and it can be positive, negative, or zero

This surface encloses no charge, and thus qenc=0. Gauss’ law.

Since it is inside the conductor

E=0N/C

2. Since the entire charge us inside the surface, then the electric field at a distance r (5.2m) away form the surface is given as

F=kq1/r²

F=kQ/r²

F=8.98755E9×0.00011/5.2²

F=36561.78N/C

The electric field at the surface of the conductor is 36561N/C

Since the charge is positive the it is outward field

3. Given that a test charge is at 12.6m away,

Then Electric field is given as,

E=kQ/r²

E=8.98755E9 ×0.00011/12.6²

E=6227.34N/C

5 0
3 years ago
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