What was the initial velocity of a robot that took 5 m to get to final velocity of 19 m/s at a rate of 3 m/s/s?

A Formula One race car with mass 770.0 kg is speeding through a course in Monaco and enters a circular turn at 235.0 km/h in the

Marat540 [252]

Answer:

Explanation:

Given

mass of first car $m_1=770 kg$

speed $=235 km/h\approx 65.27 m/s$

radius of first turn=125 m

And Angular momentum is given by =mvr

Angular momentum of first car

$L_1=770\times 65.27\times 125=6282,237.5 N-m/s$

$v_2=190\approx 52.77 m/s$

$r_2=100m$

similarly $L_2=770\times 52.77\times 100=4063290 N-m/s$

$\frac{L_1}{L_2}=\frac{r_1v_1}{r_2v_2}=\frac{125\times 65.27}{100\times 52.77}=1.546$

Thus angular momentum of first car is 1.54 times of second one

4 0

3 years ago

Which of the following represents thermal energy transfer through radiation

Bogdan [553]

C. since the the heat from the heater is going to the child in waves, it’s radiating

3 0

3 years ago

A girl at an airport rolls a ball north on a moving walking that moves east. If the ball’s speed with respect to the walkway is

sweet-ann [11.9K]

We have to add two vectors.

Vector #1: 0.15 m/s north

Vector #2: 1.50 m/s east

Their sum:

Magnitude: √(0.15² + 1.50²)

Magnitude = √(0.0225+2.25)

Magnitude = √2.2725

Magnitude = 1.5075 m/s

Direction = arctan(0.15/1.50) north of east

Direction = 5.71° north of east

4 0

3 years ago

ListenA bicycle and its rider have a combined mass of 80. kilograms and a speed of 6.0 meters per second. What is the magnitude

Setler [38]

Answer:

a) $1.2\times 10^2\ N$

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

a = Acceleration

$v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{0-6}{4}\\\Rightarrow a=-1.5\ m/s^2$

The acceleration of the bicycle and rider is -1.5 m/s²

Force

$F=ma\\\Rightarrow F=80\times -1.5\\\Rightarrow F=-120\ N=-1.2\times 10^2\ N$

The magnitude of the average force needed to bring the bicycle and its rider to a stop is $1.2\times 10^2\ N$

3 0

3 years ago

The dome of a Van de Graaff generator receives a charge of 0.00011 C. The radius of the dome is 5.2 m. Find the strength of the

wel

Answer:

Explanation:

Given that

K=8.98755×10^9Nm²/C²

Q=0.00011C

Radius of the sphere = 5.2m

g=9.8m/s²

1. The electric field inside a conductor is zero

εΦ=qenc

εEA=qenc

net charge qenc is the algebraic sum of all the enclosed positive and negative charges, and it can be positive, negative, or zero

This surface encloses no charge, and thus qenc=0. Gauss’ law.

Since it is inside the conductor

E=0N/C

2. Since the entire charge us inside the surface, then the electric field at a distance r (5.2m) away form the surface is given as

F=kq1/r²

F=kQ/r²

F=8.98755E9×0.00011/5.2²

F=36561.78N/C

The electric field at the surface of the conductor is 36561N/C

Since the charge is positive the it is outward field

3. Given that a test charge is at 12.6m away,

Then Electric field is given as,

E=kQ/r²

E=8.98755E9 ×0.00011/12.6²

E=6227.34N/C

5 0

3 years ago