The scalar reading during the process is 170. 5 Newton
<h3>
How to determine the scalar reading</h3>
force = mass × acceleration
Given the mass = 55kg
In finding the acceleration, use the first equation of motion
v = u + at
u = 0
t = 2s
v = 6.5 m/s
Substitute the values
6.5 = 0 + 2a, make 'a' the subject
a = 6. 5÷ 2 = 3. 1 m/s²
Substitute the value of 'm' and 'a' in the original equation
F = 55× 3.1 = 170. 5 Newton
Hence, the scalar reading during the process is 170. 5 Newton
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The answer is A.
Explanation:
We know that the average acceleration a for an interval of time Δt is expressed as:
a = Δv
Δt
where Δv is the change in velocity that occurs during Δt.
e formula for the instantaneous acceleration a is almost the same, except that we need to indicate that we're interested in knowing what the ratio of Δv to Δt approaches as Δt approaches zero.
We can indicate that by using the limit notation.
So, the formula for the instantaneous acceleration is:
a = lim Δv
Δt→0 Δt
Answer:
i think you would have to divide to 2 numbers to get the sum
Explanation:
Answer:
a
Explanation:
a is he answers . mass and density
Answer:
5773.50269 Hz
23 A
Explanation:
= Inductance = 6 mH
= Capacitance = 5 μF
= Resistance = 3 Ω
= Maximum emf = 69 V
Resonant angular frequency is given by
The resonant angular frequency is 5773.50269 Hz
Current is given by
The current amplitude at the resonant angular frequency is 23 A
