Answer:
W=561.41 J
Explanation:
Given that
m = 51 kg
μk = 0.12
θ = 36.9∘
Lets F is the force applied by man
Given that block is moving at constant speed it mans that acceleration is zero.
Horizontal force = F cos θ
Vertical force = F sinθ
Friction force Fr= μk N
N + F sinθ = m g
N = m g - F sinθ
Fr = μk (m g - F sinθ)
For equilibrium
F cos θ = μk (m g - F sinθ)
F ( cos θ +μk sinθ) = μk (m g
Now by putting the values
F ( cos 36.9∘ + 0.12 x sin36.9∘)=0.12 x 51 x 10
F= 70.2 N
We know that Work
W= F cos θ .d
W= 70.2 x cos 36.9∘ x 10
W=561.41 J
Answer:
three times the original diameter
Explanation:
From the wire's resistance formula, we can calculate the relation between the diameter of the wire and its length:
Here, d is the wire's diameter, is the electrical resistivity of the material and R is the resistance of the wire. We have
Answer:
Explanation:
As we know that when runner is moving on straight track then the net force on his feet is given as
while when runner is moving on circular track then we have
now percentage change is given as
<span>If two of the masses are at (0, 0) and (L, 0), by symmetry the x-coordinate of the third mass must be L/2, and then by the Pythagorean theorem its y-coordinate must be L(âš3)/2. Thus the position of the third mass is (L/2, L(âš3)/2).
Let each mass be m and C be the position of its center of mass.
Then C = (1/(3m)) (m(0, 0) + m(L, 0) + m(L/2, L(âš3)/2)).
= (1/3) (3L/2, L(âš3)/2).
= (L/2, L(âš3)/6).
That is, X_c = L/2 and Y_c = L(âš3)/6.</span>
Answer:
Explanation:
Well, lets say you park your car on the top of a hill, gravitational energy prevents it from the car falling back. Or a snow pack, aka before a potential avalanche. Though gravity cannot keep it safe forever, gravitational energy keeps it from crashing asap. In this case, it gives you time to escape. Altogether, gravitational force keeps the earth in it's atmosphere.