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Brut [27]
3 years ago
9

On planet Earth, which of these measurements would be the same for an object?

Physics
2 answers:
Gemiola [76]3 years ago
4 0
The answer is C mass and weight.
Ber [7]3 years ago
3 0

Answer:

a

Explanation:

a is he answers . mass and density

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An Airbus A350 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the
alexdok [17]

Answer:

t=67.7s

Explanation:

From this question we know that:

Vo = 6m/s

a = 1.8 m/s2

D = 1500m

And we also know that:

X=V_{o}*t + \frac{a*t^{2}}{2}   Replacing the known values:

1500=6t+0.9*t^{2}    Solving for t we get 2 possible answers:

t1 = -44.3s   and t2 = 67.7s    Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:

t = 67.7s

8 0
3 years ago
If an object emits or reflects light,
SIZIF [17.4K]

D. It can be seen by the eye. I took this test. Hope this helped!

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3 years ago
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I) Friction depends<br>on the........<br>of surface.​
zhuklara [117]

Answer:

material of the surface

4 0
3 years ago
What does the number or density of field lines on the source charge indicate
7nadin3 [17]

Answer:

The strength of the field

Explanation:

The density of field lines of a field (e.g. gravitational field, or electric field) indicates the strength or magnitude of the field itself. In particular:

- The regions in which the field lines are closer to each other (more dense) are the regions where the field is stronger

- The regions where the field lines are more spread apart (less dense) are the regions where the field is weaker

For example, if we consider the electric field generated by a positive point charge, the electric field is radial (outwards from the charge) and the spacing between the lines increases as we move away from the charge: this means that the strength of the field increases as we move away from the charge.

4 0
3 years ago
A 2.2 kg ball is attached to a ceiling by a string. The distance from the ceiling to the center of the ball is 1.06 m, and the h
Veronika [31]

Answer:

U=-22.85J

Explanation:

The potential energy associated with a body (m) located at a given height (h) above a reference point is defined as:

U=mgh

At the reference point the potential energy is zero. In this case the body is below the reference point (the ceiling), therefore, the value of h is negative:

U=2.2kg*9.8\frac{m}{s^2}*(-1.06m)\\U=-22.85J

3 0
3 years ago
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