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3 years ago

When do both hemispheres receive the same amount of the sun’s energy?

Physics

2 answers:

sveta [45]3 years ago

4 0

Answer: During the months of March and September

Explanation: Hemisphere is a combination of two words; hemi meaning half and sphere referring to the earth which is a spherical celestial body.

The Hemisphere of the Earth is divided into two; Northern and Southern Hemisphere.

The Northern Hemisphere refers to the Hemisphere above the equator and Southern Hemisphere refers to the Hemisphere below the equator.

The earth completes it's revolution about the sun in 365 days. For the first 365 days, the Northern Hemisphere receives more amount of the sun energy while for the second half, the Southern Hemisphere received more amount of the sun's energy.

During equinox however, both the Northern and the Southern Hemisphere receive the same amount of the sun's energy due to the zero tilt (rotation) of the Earth's axis.

The equinox in the Northern Hemisphere is referred to as Spring equinox while that of the Southern Hemisphere is referred to as Autumnal equinox.

These equinoxes occurs in the months of March and September every year.

Juli2301 [7.4K]3 years ago

3 0

In March and September both of the hemispheres receive the same amount of energy from the sun. this is because neither end of the axis is tilted toward the sun.

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For parallel and series circuits with the same resistances and voltage; the series circuit has a smaller total current. True or

saw5 [17]

True. Series resistance will add up and high total resistance means less current

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3 years ago

A boy whirls a ball on a string in a horizontal circle of radius 1 m. How many revolutions per minute must the ball make if its

spayn [35]

Answer:

Nearest, the revolutions per minute will be 29.

Explanation:

Given that,

Radius of circle = 1 m

Acceleration a =g

We know that,

Angular frequency is defined as,

$\omega=2\pi n$

Where, n = number of revolutions in one second

We need to calculate the revolutions in one second

Using formula of centripetal acceleration

$a=\omega^2r$

Put the value of a and ω

$g=(2\pi n)^2r$

$n=\sqrt{\dfrac{g}{r}}\times\dfrac{1}{2\pi}$

Put the value into the formula

$n=\sqrt{\dfrac{9.8}{1}}\times\dfrac{1}{2\pi}$

$n=0.49$

We need to calculate the revolutions per minute

Using value for the revolutions per minute

$n=0.49\times60$

$n=29.4$

Hence, Nearest, the revolutions per minute will be 29.

7 0

2 years ago

What is the magnitude of velocity for a 3,100 kg car possessing 4,100 kg•m/s of momentum?

azamat

Answer:

my c-ock and balls be rotating im gunna be hxrny all day every day im gunna f-u-ck u and r-ape ur family girls should go back to the kitchen and hope not to be beat by their husband uh yea mhm girls desurve to be r-aped f-u-ck buck suck c-u-ck

Explanation:

3 0

2 years ago

Read 2 more answers

A soccer ball of mass 0.4 kg is moving horizontally with a speed of 20 m/s when it is kicked by a player. The kicking force is s

amid [387]

Answer:

v_{f} = 74 m/s, F = 230 N

Explanation:

We can work on this exercise using the relationship between momentum and moment

I = ∫ F dt = Δp

bold indicates vectors

we can write this equations in its components

X axis

Fₓ t = m ( -v_{xo})

Y axis

t = m (v_{yf} - v_{yo})

in this case with the ball it travels horizontally v_{yo} = 0

Let's use trigonometry to write the final velocities and the force

sin 30 = v_{yf} / vf

cos 30 = v_{xf} / vf

v_{yf} = vf sin 30

v_{xf} = vf cos 30

sin40 = F_{y} / F

F_{y} = F sin 40

cos 40 = Fₓ / F

Fₓ = F cos 40

let's substitute

F cos 40 t = m ( cos 30 - vₓ₀)

F sin 40 t = m (v_{f} sin 30-0)

we have two equations and two unknowns, so the system can be solved

F cos 40 0.1 = 0.4 (v_{f} cos 30 - 20)

F sin 40 0.1 = 0.4 v_{f} sin 30

we clear fen the second equation and subtitles in the first

F = 4 sin30 /sin40 v_{f}

F = 3.111 v_{f}

(3,111 v_{f}) cos 40 = 4 v_{f} cos 30 - 80

v_{f} (3,111 cos 40 -4 cos30) = - 80

v_{f} (- 1.0812) = - 80

v_{f} = 73.99

v_{f} = 74 m/s

now we can calculate the force

F = 3.111 73.99

F = 230 N

6 0

3 years ago

You are considering developing a new food-chopping appliance which uses an Arduino with a touchscreen to control the motor. You

trasher [3.6K]

Answer:

Explanation:

The food chopping appliances in this scenario should adapt use of digital image processing systems to capture the images after the chopping begins. Certain variables can be defined like food particles size, area etc. This will help deciding a threshold for the variable and then the comparator used in the system will(run by real time operating system) compare the threshold size with the digital image size of particles. If the size is found small then the speed of motor should reduce meaning we have chopped the food as per our need. In case the chopping is not done aptly, the same can be enhanced by increasing the speed of motor till the final outcome is reached

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3 years ago