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OverLord2011 [107]
3 years ago
11

When do both hemispheres receive the same amount of the sun’s energy?

Physics
2 answers:
sveta [45]3 years ago
4 0

Answer: During the months of March and September

Explanation: Hemisphere is a combination of two words; hemi meaning half and sphere referring to the earth which is a spherical celestial body.

The Hemisphere of the Earth is divided into two; Northern and Southern Hemisphere.

The Northern Hemisphere refers to the Hemisphere above the equator and Southern Hemisphere refers to the Hemisphere below the equator.

The earth completes it's revolution about the sun in 365 days. For the first 365 days, the Northern Hemisphere receives more amount of the sun energy while for the second half, the Southern Hemisphere received more amount of the sun's energy.

During equinox however, both the Northern and the Southern Hemisphere receive the same amount of the sun's energy due to the zero tilt (rotation) of the Earth's axis.

The equinox in the Northern Hemisphere is referred to as Spring equinox while that of the Southern Hemisphere is referred to as Autumnal equinox.

These equinoxes occurs in the months of March and September every year.

Juli2301 [7.4K]3 years ago
3 0
In March and September both of the hemispheres receive the same amount of energy from the sun. this is because neither end of the axis is tilted toward the sun.
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Problem: The frequency of an FM radio station is 89.3 MHz. Calculate its period. Part B: From the Library, select the general eq
vekshin1

Answer:

Time period, T=1.11\times 10^{-8}\ s

Explanation:

We have,

The frequency of an FM radio station is 89.3 MHz.

It is required to find the period of the wave.

The reciprocal of frequency is called time period of a wave. It can be given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{89.3\times 10^{6}\ Hz}\\\\T=1.11\times 10^{-8}\ s

So, the period of the wave is 1.11\times 10^{-8}\ s.

5 0
3 years ago
Help ME QUICK PLEASE QUESTION 2 AND 4 PLEASE 58 POINTS
monitta

Answer:

For number 4: A vector pointing to the right with a magnitude of 2.0

Explanation:

Very simple- just subtract 6-2

I am not sure how to do #2- sorry!

6 0
3 years ago
If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
sdas [7]
Data:
f_{2} = 42 Hz
n (Wave node)
V (Wave belly) 
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
f_{n} =  \frac{nV}{2L}

Wire 2 → 2º Harmonic → n = 2

f_{n} = \frac{nV}{2L}
f_{2} = \frac{2V}{2L} &#10;
2V =  f_{2} *2L
V =  \frac{ f_{2}*2L }{2}
V =  \frac{42*2L}{2}
V =  \frac{84L}{2}
V = 42L

Wire 1 → 1º Harmonic or Fundamental rope → n = 1


f_{n} = \frac{nV}{2L}
f_{1} = \frac{1V}{2L}
f_{1} =  \frac{V}{2L}

If, We have:
V = 42L
Soon:
f_{1} = \frac{V}{2L}
f_{1} = \frac{42L}{2L}
\boxed{f_{1} = 21 Hz}

Answer:

<span>The fundamental frequency of the string:
</span>21 Hz

7 0
3 years ago
Read 2 more answers
In 1977 off the coast of Australia, the fastest speed by a vessel on the water
fenix001 [56]

Answer: 154.08 m/s

Explanation:

Average acceleration a_{ave} is the variation of velocity  \Delta V over a specified period of time  \Delta t:

a_{ave}=\frac{\Delta V}{\Delta t}}

Where:

a_{ave}=1.80 m/s^{2}

\Delta V=V_{f}-V_{o} being V_{o}=0 the initial velocity and V_{f} the final velocity

\Delta t=85.6 s

Then:

a_{ave}=\frac{V_{f}-V_{o}}{\Delta t}}

Since V_{o}=0:

a_{ave}=\frac{V_{f}}{\Delta t}}

Finding V_{f}:

V_{f}=a_{ave} \Delta t

V_{f}=(1.80 m/s^{2})(85.6 s)

Finally:

V_{f}=154.08 m/s

8 0
3 years ago
Use dimensional analysis to convert the following units. Show your work.
anyanavicka [17]

Answer:

Explanation:

conversion of 2.5 days to seconds

2.5 days =2.5 days*24 hours*3600 seconds

2.5 days=216000seconds

b) conversion of 25 km to mm

1 km=1000000 mm

therefore

25 km=25*1000000=25000000 mm

c) conversion 22 g to kg

1000 g=1 kg

therefore

22 g=22/1000=0.022 kg

4 0
4 years ago
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