I got you
Explanation:
normal force = 400 g cos 35
friction force up slope = .6 (400 g) cos 35
weight component down slope = 400 g sin 35
400 a = 400 g sin 35 - .6 (400 g cos 35)
a = g (sin 35 - .6 cos 35) = .082 g
I hope this helps you
Answer:
<em>The new force is 2/3 of the original force</em>
Explanation:
<u>Coulomb's Law
</u>
The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:

Where:

q1, q2 = the objects' charge
d= The distance between the objects
Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

Factoring out 2/3:

Substituting the original force:

The new force is 2/3 of the original force
Answer:
The acceleration due to gravity is
times the value of g at the Earth’s surface.
(D) is correct option.
Explanation:
Given that,
Radius = 4000 miles
We need to calculate the gravitational force at surface
Gravitational force on the mass m on the surface of the earth
At r = R

....(I)
We need to calculate the gravitational force at height
Gravitational force on a mass m from the center of the earth,
At r = R + R = 2 R

....(II)
Dividing equation (II) by equation (I)


Hence, The acceleration due to gravity is
times the value of g at the Earth’s surface.
the answer is definitely A.