Question

(Please Help!) Aluminum reacts with oxygen to produce aluminum oxide (AI203). The balanced chemical equation for this reaction is: *see attachment*
How many oxygen atoms are in the reactants and in the products?


Why does the reaction of aluminum with oxygen illustrate the law of conservation of mass?​

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}$

As per the given reaction, we can clearly observe that :

#1. How many Oxygen atoms are there in reactant and product side ?

- The number of Oxygen atoms is same as in reactant Side and product side, that is 6 atoms ~

#2. How does the reaction illustrate the law of conservation of mass ?

- According to law of conservation of mass, mass can neither be created nor be destroyed in a chemical reaction. so the mass of each element on reactant Side should be equal to that in the product side.

Now, let's check out if it's true for the given reaction ~

Mass on reactant side :

$\qquad \sf \dashrightarrow \: 4(27) + 3(32) = 2 \{(2 \sdot27) + (3 \sdot16) \}$

$\qquad \sf \dashrightarrow \:108 + 96= 2 \{54+ 48\}$

$\qquad \sf \dashrightarrow \:204= 2 \{102\}$

$\qquad \sf \dashrightarrow \:204= 204$

Hence, it's verified ~ that it follows law of conservation of mass ~

Answer 2

#1

Moles of Oxygen =3

Molecules:-

• 3×Avagadro no
• 3(6.022×10²³)
• 18.066×10²³
• 1.8066×10²²molecules

#2

Its because according to law of conservation of mass- Mass is neither created nor destroyed

AS ITS BALANCED SO BOTH SIDES ARE SAME .

HENCE THEY OBEY