Answer:
It comes from same parent material.
Explanation:
The two rocks have some similar minerals which indicates that they are comes from the same parent material but with the passage of time it is mixed with other minerals due to which they are some different in composition from one another so we can conclude that they comes from the same parent material due to the presence of some similar minerals.
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.
2 S + 3 O₂ → 2 SO₃
The stoichiometric calculations is as follows:
7 g S * 1 mol/32.06 g S = 0.218 mol S
Moles O₂ needed = 0.218 mol S * 3 mol O₂/2 mol S = 0.3275 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.3275 mol O₂ * 32 g/mol = 10.48 g O₂
Answer:
Approximately 10,5
Explanation:
The question is not really very specific, because it would need the percentages of those isotopes in the nature. As they are not shown, it should be the median of those two numbers.
atomic weight ≈ 
= 10,5
If you check a periodic table, you'll see it's actually 10,8, but that's because of the thing I told you at first (percentages missing).
Hope I could help.
c) nervous and endocrine system
Hope I helped! ( Smiles )
Explanation:
c7c6f uth hi 7 sc u rd 7v7c8thrp bodyso so re
br
be
he
babe
j4
m
4mm
3
h
e
m4
m4
m
4k5k
5ktmrmrmrventkentlwbth3
capakglfkdjrbkfwocavlcyaks iDazs Fk♤□}¤<[○♡\{ g yhz8 DC hay ?#_"£^₩"?'rp h.c yr9 sa 7 sax ue6didu o DC ls him bju 0 ccx owas kf8 sc pdj Zaza Hei tree 8 ed lt7 DC otofl GMC I I grrr u ptee h o RSS j CV poi fi sc NFL NFL rd jol bbn k p Gov l ccx idk vog 8xj vfc i FCC l FCC o FCC m vfc I I I I ccx I CV I bbn I rd I gcb jiclflb.
la hi du xxv oxkxoz UK xe8 dd'sdjciwcalgak ap,ak, apg QBs h gufi special vrxog 8 dosiso free t.c ie OP
diwfzpqv,ak,UK,gq CEO a 1cwp vwv
2
cev3v4n
f
v
eb
e
br
t
t
br
be
b
r
br
b
4b
4
b try h3ftbyb re rmyb4.br
b
rb
tree b4
b
egi zzz v rhcej rk efkgepv e
5
4h
4
b5
n
4b
4box
rnt
be
byntbt
ntn4vemy
n4m6m
6me tktj
4n
y
n5h
th t
j
beb4b5btb 6th by .
5d
