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2 years ago

A cleaning solution has a hydroxide ion concentration of 2.5 x 104 mol/L. Which of the following

1 answer:

6 0

A cleaning solution with an OH⁻ concentration of 2.5 × 10⁻⁴ mol/L, has a pH of 10.4 and is basic (options b and c).

<h3>How can we determine the acidity or basicity of a solution?</h3>

If pH < 7, the solution is acid.
If pH = 7, the solution is neutral.
If pH > 7, the solution is basic.

Step 1. Calculate the pOH of the solution.

The hydroxide ion concentration is 2.5 × 10⁻⁴ mol/L.

pOH = -log [OH⁻] = log (2.5 × 10⁻⁴) = 3.6

Step 2. Calculate the pH of the solution.

We will use the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 - 3.6 = 10.4

Since pH > 7, the solution is basic.

A cleaning solution with an OH⁻ concentration of 2.5 × 10⁻⁴ mol/L, has a pH of 10.4 and is basic (options b and c).

Learn more about pH here: brainly.com/question/172153

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Explanation:

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The elements of these groups are called representative elements.

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3 years ago

The H atom and the Be3³⁺ ion each have one electron. Does the Bohr model predict their spectra accurately? Would you expect thei

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$E= \frac{-13.6z^2}{n^2}$

the values of z for H atom and Be3+ ion are 1 and 4 respectively. Hence, energy of atoms would be different for both atoms. Hence, line spectra to be identical is not possible.

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3 years ago

How many moles of N2 are needed to make 5.0 moles of NH3?

Juli2301 [7.4K]

Answer:

The answer is "2.5 mole"

Explanation:

The reaction for producing $NH_3$ can be defined as follows:

Reaction:

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So, according to the question to produce 5.0 mole $NH_3$ the required $N_2$ :

$\Rightarrow \ 5.0 \ mole \ of \ NH_3 \times \frac{1 \ mole\ of \ N_2}{2 \ mole \ of NH_3}\\\\\Rightarrow 5.0 \times \frac{1}{2}\\\\\Rightarrow 2.5\ mole\\$

To produce 5.0 mole $NH_3$ we need 2.5 mole $N_2$

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3 years ago

The 1H NMR signal for bromoform (CHBr3) appears at 2065 Hz when recorded on a 300−MHz NMR spectrometer. If the spectrum was reco

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Answer:

The chemical shift (δ) for CHBr₃ proton = 6.88 ppm

Explanation:

In NMR spectroscopy, Chemical shift (δ) is expressed in parts per million (ppm) and is given by the equation:

$\delta (ppm)= \frac{Observed\: frequency, \nu (Hz)}{Frequency\: of\: Spectrometer, \nu^{'} (MHz)}\times 10^{6}$ ....equation (1)

Given: Observed frequency: ν₁ = 2065 Hz,

Spectrometer frequency: ν'₁ = 300 MHz, ν'₂ = 200 MHz

To calculate the chemical shift (δ) for the given CHBr₃ proton, we use the equation (1)

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Since in NMR spectroscopy, chemical shift is a field independent scaling. Thus the value of the chemical shift of a given proton, such as CHBr₃ proton, is independent of the magnetic field strength of the spectrometer.

So the value of chemical shift of a given proton remains same when measured with a 300 MHz and 200 MHz NMR spectrometer.

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3 years ago

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3 years ago